Answer:
If we increase the temperature in a reactor by 54 degrees Fahrenheit [54°F], the temperature will increase by 12.22 degrees Celsius [12.22 ⁰C]
Explanation:
To determine the number of degrees Celsius the temperature will be increased, we convert from Fahrenheit to Celsius.
Converting from Fahrenheit to degree Celsius
54°F -----> °C
54 = 1.8°C + 32
54-32 = 1.8°C
22 = 1.8°C
°C = 22/1.8
= 12.22 °C
Thus, 54°F -----> 12.22 °C
Therefore, If we increase the temperature in a reactor by 54degrees Fahrenheit [54°F], the temperature will increase by 12.22 degrees Celsius [12.22 ⁰C]
Answer:
Explanation:
reactance of inductor = wL = 2 X 3.14 X 60 X 1.2 X 10⁻³ = .45 ohm.
reactance of capacitor = 1/wC = 1/( 2 X 3.14 X 60 X 1.8 X 10⁻⁶ ) = 1474.4
Impedence of the circuit =[ R² + ( I/wC - wL) ]¹/² = [250² + ( 1474.4-.45 )]¹/²
Impedence = 1495 ohm.
RMS Voltage = 120/ 1.414 = 84.86 V
current = 84.86 / 1495 = 0.0576
Potential over resistance = 0.0576 x 250 = 14.2 V.
Answer:
v₀ = 9,798 ft / s
Explanation:
We can solve this problem with kinematics in one dimension, when the train stops the speed is zero, the acceleration is negative so that the train stops. Let's use the equation
v² = v₀² - 2 a d
v = 0
v₀ = √2 a d
In the problem it indicates that the acceleration is g / 2, we substitute
v₀ = √2 (g / 2) d
Let's calculate
v₀ = √ 2 32/2 3 = √32 3
v₀ = 9,798 ft / s
Explanation:
Given
Range of ball =7.88 m
Initial speed=13.1 m/s
and we know
Range of Projectile is
(b)other angle would be complementary of 
This is a speed/time graph.
The slope of the graph at each point is the time rate of change of speed
at that point, and THAT's the definition of the magnitude of acceleration.
The slope of the curve is zero at both ' A ' and ' B ', so acceleration is
zero at both of those points.
That seems to be exactly what choice-c says.
