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Yakvenalex [24]
2 years ago
15

An object with a mass of 21 kilograms is lifted through a distance of 7 meters how much work is done

Physics
1 answer:
Shtirlitz [24]2 years ago
4 0
We have: W = F × s
W = m×g×s
Here, m = 21 Kg  [ Given ]
g = 9.8 m/s²         [ constant value for earth system ] 
s = 7 ,                  [ Given ]

Substitute their values into the expression:
W = 21×9.8×7
W = 1440.6 Joules

In short, Your Final Answer would be 1440.6 J

Hope this helps!
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Why does the moon turn red during a lunar eclipse?.
SOVA2 [1]

Answer:

During a lunar eclipse, the Moon turns red because the only sunlight reaching the Moon passes through Earth's atmosphere. The more dust or clouds in Earth's atmosphere during the eclipse, the redder the Moon will appear.

4 0
2 years ago
How can the direction of a tensional force be changed without diminishing the force?
RSB [31]

Given what we know, we can confirm that the tensional force of a system can in theory be changed without diminishing its force through the use of an ideal pulley.

<h3>What is an ideal pulley?</h3>
  • A pulley is a small wheel through which a string or chain is run.
  • These are used in order to change the direction of a force.
  • An ideal pulley would be one in which there is no friction and the pulley itself would have no mass.
  • Therefore, the force would be able to change directions without giving part of its force to the pulley system.

Therefore, we can confirm that the only known way to change the direction of a force without diminishing its value would be through the use of a frictionless and massless pulley system otherwise known as an ideal pulley.

To learn more about Friction visit:

brainly.com/question/13357196?referrer=searchResults

4 0
2 years ago
Consider a stone in free fall on a planet with gravitational acceleration 3.4 m/s^2. Suppose you would like the stone to experie
Stella [2.4K]

Answer:

Angle of incline is 20.2978°

Explanation:

Given that;

Gravitational acceleration on a planet a = 3.4 m/s²

Gravitational acceleration on Earth g = 9.8 m/s²

Angle of incline = ∅

Mass of the stone = m

Force on the stone along the incline will be;

F = mgSin∅

F = ma

The stone has the same acceleration as that of the gravitational acceleration on the planet.

so

ma = mgSin∅

a = gSin∅

Sin∅ = a / g

we substitute

Sin∅ = (3.4 m/s²) / (9.8 m/s²)

Sin∅ = 0.3469

∅ = Sin⁻¹( 0.3469 )

∅ = 20.2978°

Therefore, Angle of incline is 20.2978°

8 0
3 years ago
A helicopter has blades of length 4.0 m rotating at 3.0 rev/s in a horizontal plane.If the vertical component of the Earth’s mag
VARVARA [1.3K]

Answer:

Induced emf, \epsilon=9.79\times 10^7\ volts

Explanation:

Given that,

Length of the helicopter, l = 4 m

Angular speed of the helicopter, \omega=3\ rev/s=18.84\ rad/s

The vertical component of the Earth’s magnetic field is, B=6.5\times 10^5\ T

We need to find the induced emf between the tip of a blade and the hub. The induced emf in terms of angular velocity of an rotating object is given by :

\epsilon=\dfrac{1}{2}B\omega l^2

\epsilon=\dfrac{1}{2}\times 6.5\times 10^5\times 18.84\times (4)^2

\epsilon=9.79\times 10^7\ volts

So, the induced emf between the tip of a blade and the hub is \epsilon=9.79\times 10^7\ volts. Hence, this is the required solution.

5 0
3 years ago
(10p+15,15-10q)=(25,5)​
Harrizon [31]
63783626736377474737377447
8 0
2 years ago
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