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Soloha48 [4]
3 years ago
6

The boiling point of another member of this homologous series was found to be 309 KK. What is the likely molecular formula for t

his compound?
Chemistry
1 answer:
Ganezh [65]3 years ago
8 0

Answer: Pentane C5H12

Explanation:

The boiling point of a substance is simply defined as the temperature whereby a liquid's vapor pressure is equal to the pressure that is surrounding the liquid and hence, the liquid will changes into vapor.

The likely molecular formula for this compound is Pentane i.e C5H12 due to the fact that its boiling point is between Butane with formula C4H10 and Hexane with formula C6H14 boiling points.

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A student determines that she used 0.0665 mol of sodium hydroxide (NaOH) to completely titrate 25.00 mL of sulfuric acid solutio
AysviL [449]

To determine the concentration of one solution which is specifically basic or acidic solution through taking advantage on its points of equivalence, titration analysis is done.

Let us determine the reaction for the titration below:

2NaOH +2H2SO4 = Na2SO4 +2H2O

 

So,

0.0665 mol NaOH (2 mol H2SO4/ 2mol NaOH) / .025 L solution 

= 2.62 M H2SO4


The answer is the fourth option: 

<span>2.62 M</span>
7 0
3 years ago
Read 2 more answers
In terms of energy, how would you classify the following chemical reaction? 2CuO + 315 kJ → 2Cu + O2
Snowcat [4.5K]
"Endothermic" is the way among the following choices given that you would <span>classify the following chemical reaction, in terms of energy. The correct option among all the options that are given in the question is the second option or option "B". I hope that the answer has come to your help.</span>
6 0
3 years ago
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If three potatoes have a mass of 667 g, what will be the mass of 100 potatoes? A. 200 kg B. 22.2 kg C. 2223 g D. 20.0 kg
adell [148]

Answer: B- 22.2 kg

Explanation: If three potatoes have mass of 667 g that means that each potato weighs 667/3= 222.33 g (approx) so 100 potatoes must be 100*222.33= 22233 g which equals 22.2 kg because 1 g=1000 kg

8 0
3 years ago
How many milligrams of MgI2 must be added to 257.7 mL of 0.087 M KI to produce a solution with [I−] = 0.1000 M?
lbvjy [14]

Answer:

The answer is 465.6 mg of MgI₂ to be added.

Explanation:

We find the mole of ion I⁻ in the final solution

C = n/V -> n = C x V = 0.2577 (L) x 0.1 (mol/L) = 0.02577 mol

But in the initial solution, there was 0.087 M KI, which can be converted into mole same as above calculation, equal to 0.02242 mol.

So we need to add an addition amount of 0.02577 - 0.02242 = 0.00335 mol of I⁻. But each molecule of MgI₂ yields two ions of I⁻, so we need to divide 0.00335 by 2 to find the mole of MgI₂, which then is 0.001675 mol.

Hence, the weight of MgI₂ must be added is

Weight of MgI₂ = 0.001675 mol x 278 g/mol = 0.4656 g = 465.6 mg

4 0
3 years ago
Use the molar solubility 3.27×10−11m in pure water to calculate ksp for nis.
Ne4ueva [31]

Answer:

Ksp = 1.07x10⁻²¹

Explanation:

Molar solubility is defined as moles of solute can be dissolved in 1L.

Ksp for NiS is defined as:

NiS(s) ⇄ Ni²⁺(aq) + S²⁻(aq)

Ksp = [Ni²⁺] [S²⁻]

As molar solubility is 3.27x10⁻¹¹M, concentration of [Ni²⁺] and [S²⁻] is 3.27x10⁻¹¹M for both.

Replacing:

Ksp = [3.27x10⁻¹¹M] [3.27x10⁻¹¹M]

<em>Ksp = 1.07x10⁻²¹</em>

<em></em>

4 0
2 years ago
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