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2 years ago

If you have a density of 3 g/mL and a mass of 15 g, what is the volume?

Chemistry

2 answers:

Alexandra [31]2 years ago

6 0

Answer:

5mL

Explanation:

ρ=m/V

V=m/ρ=15/3=5 mL

Hope, this helps you.

marta [7]2 years ago

3 0

Answer:

15 ml

Explanation:

Volume = mass / density.

So our answer is 15 / 3 = 15 mL

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When energy is transferred from the air to the water, what happens to most of the energy? A. It travels through the water. B. It

BigorU [14]

Answer: Option (A) is the correct answer.

Explanation:

When energy is transferred from the air to the water then energy is absorbed by the water molecules.

This energy travels through one molecule of water to another molecule of water by the process of convection.

Thus, we can conclude that when energy is transferred from the air to the water, then it travels through the water.

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3 years ago

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Where are human cells located (in living organisms)

defon

All inside and out in the human body

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2 years ago

A comic book villain is holding you at gun point and is making you drink a sample of acid he gives you a beaker with 100 ml of a

miss Akunina [59]

Answer:

b. 10 mL

Explanation:

First we calculate the amount of H⁺ moles in the acid:

pH = -log [H⁺]

[H⁺] = $10^{-pH}$

[H⁺] = 10⁻⁵ = 1x10⁻⁵M

100 mL ⇒ 100 / 1000 = 0.100 L

1x10⁻⁵M * 0.100 L = 1x10⁻⁶ mol H⁺

In order to have a neutral solution we would need the same amount of OH⁻ moles.

We can use the pOH value of the strong base:

pOH = 14 - pH

pOH = 14 - 10 = 4

Then we calculate the molar concentration of the OH⁻ species in the basic solution:

pOH = -log [OH⁻]

[OH⁻] = $10^{-pOH}$ = 1x10⁻⁴ M

If we use 10 mL of the basic solution the number of OH⁻ would be:

10 mL ⇒ 10 / 1000 = 0.010 L

1x10⁻⁴ M * 0.010 L = 1x10⁻⁶ mol OH⁻

It would be equal to the moles of H⁺ so the answer is b.

7 0

3 years ago

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How many significant figures are in each of the following measurements? (c) 0.03003 kg (f) 3.8200 x 103 L (a) (d) 0.00450 m 35.0

erica [24]

Answer:

c =four significant figures = 3003

f = Four significant figures = 3820

d =(i) three significant figures = 450

d =(ii) Six significant figures = 35.0445

b = significant figures = 59.0001

e = five significant figures = 67000

Explanation:

c = 0.03003 kg

four significant figures = 3003

f = 3.8200 × 10³ L

Four significant figures = 3820

d =(i) 0.00450 m and (ii) 35.0445 g

(i) three significant figures = 450

(ii) Six significant figures = 35.0445

b = 59.0001 cm

six significant figures = 59.0001

e = 67000

five significant figures = 67000

The given measurement have five significant figures 41006. this measurement can be rounded to three significant figures i.e, 0.410 g.

All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.

Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.

Zero between the non zero digits are consider significant like 104 consist of three significant figures.

The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.

8 0

3 years ago

If 3 moles of H2 react with two moles of o2 what is limiting reactant

Dominik [7]

H₂ is the limiting reactant.

Explanation:

H₂ reacts with O₂

The reaction would be

2H₂ + O₂ → 2H₂O

According to the balanced equation, 2 moles of H₂ reacts with 1 mole of O₂ to form 2 moles of H₂O.

The ratio of usage of H₂ and O₂ is 2 : 1 respectively

If 3 moles of H₂ and 2 moles of O₂ are present then:

3 moles of H₂ would require 1.5 moles of O₂ ( 2 : 1 of H₂ and O₂ )

Out of 2 moles of O₂, 1.5 moles would be used and 0.5 mole would be in excess.

Therefore, H₂ is the limiting reactant as the number of moles of H₂ are not enough to use all the O₂.

8 0

3 years ago