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insens350 [35]
3 years ago
7

Which of the following weak interactions would require the least amount of energy to disrupt? Group of answer choices

Chemistry
2 answers:
SpyIntel [72]3 years ago
8 0

Answer: Option (c) is the correct answer.

Explanation:

A hydrogen bond is defined as a weak bond that is formed between an electropositive atom (generally hydrogen atom) and an electronegative atom like oxygen, nitrogen and fluorine.

An ionic bond is defined as a bond formed between a metal and a non-metal and in this bond transfer of electron takes place from metal to non-metal. And, due to the presence of opposite charges on the combining atoms there exists a strong force of attraction.

Vander waal forces are defined as the weak electric forces which tend to attract neutral molecules towards each other in gases, liquefied and solidified gases.

Vander waal forces are very weak forces.

Thus, we can conclude that Van der walas interactions are weak interactions would require the least amount of energy to disrupt.

krek1111 [17]3 years ago
3 0

Answer:

Van der waals force

Explanation:

Van der waals force is the weakest and would require less energy to disperse. It’s also known as London forces and mostly found with the halogen groups which undergoes sublimation( solid-gas) change. This force is responsible for this feature.They are usually easily dispersed hence it can also be called dispersion forces

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Suppose that 0.48 g of water at 25∘C∘C condenses on the surface of a 55-gg block of aluminum that is initially at 25∘C∘C. If the
GarryVolchara [31]

Answer : The final temperature of the metal block is, 25^oC

Explanation :

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of aluminum = 55 g

m_2 = mass of water = 0.48 g

T_{final} = final temperature = ?

T_1 = temperature of aluminum = 25^oC

T_2 = temperature of water = 25^oC

c_1 = specific heat of aluminum = 0.900J/g^oC

c_2 = specific heat of water= 4.184J/g^oC

Now put all the given values in equation (1), we get

55g\times 0.900J/g^oC\times (T_{final}-25)^oC=-[0.48g\times 4.184J/g^oC\times (T_{final}-25)^oC]

T_{final}=25^oC

Thus, the final temperature of the metal block is, 25^oC

6 0
3 years ago
What charge would you expect for an formed by S?
sp2606 [1]

Answer:

in this the correct answer is option 2.

6 0
2 years ago
The valence electrons occur in what part of the atom?
shutvik [7]
The correct answer to the question that is stated above is letter  c, <span> the outer electron shell.</span>

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>> <span>Valence electrons are </span>electrons<span> that are associated with an </span>atom<span>, and that can participate in the formation of a </span>chemical bond.
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Explanation:

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This means that if V is constant then

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3 years ago
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amm1812

Answer:

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