Answer:
1.7 * 10^-5
Explanation:
1- get the number of moles of PbCl2:
number of moles = mass / molar mass
number of moles = 0.45 / 278.1 = 1.618 * 10^-3 moles
2- get the concentration of Pb2+:
molarity = number of moles of solute / volume of solution in liters
molarity = (1.618 * 10^-3) / (0.1) = 0.0162 M
3- getting concentration of Cl-:
<span>PbCl2(s) <==> Pb2+(aq) + 2Cl-(aq)
</span>We can note that:
For a certain amount of Pb2+ formed, twice this amount of Cl- is formed.
This means that:
for 0.0162 M of Pb2+, 2*0.0168 = 0.0324 M of Cl- is formed
4- getting Ksp:
Ksp = [Pb2+][Cl-]²
Ksp = (0.0162)*(0.0324)²
Ksp = 1.7 * 10^-5
Hope this helps :)
<h2><em>It is True that every bronsted-lowry acid is also a lewis acid </em></h2>
Answer:
Therefore we can say that the total number of electrons present in $ p - $ orbital of chlorine atoms is eleven.
Explanation:
<u>Answer:</u> The concentration of the diluted solution is 0.4788M
<u>Explanation:</u>
To calculate the concentration of the diluted solution, we use the following equation:

where,
are the molarity and volume of HCl solution
are the molarity and volume of the diluted HCl solution.
We are given:

Putting values in above equation, we get:

Hence, the concentration of the diluted solution is 0.4788M