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insens350 [35]
3 years ago
7

Which of the following weak interactions would require the least amount of energy to disrupt? Group of answer choices

Chemistry
2 answers:
SpyIntel [72]3 years ago
8 0

Answer: Option (c) is the correct answer.

Explanation:

A hydrogen bond is defined as a weak bond that is formed between an electropositive atom (generally hydrogen atom) and an electronegative atom like oxygen, nitrogen and fluorine.

An ionic bond is defined as a bond formed between a metal and a non-metal and in this bond transfer of electron takes place from metal to non-metal. And, due to the presence of opposite charges on the combining atoms there exists a strong force of attraction.

Vander waal forces are defined as the weak electric forces which tend to attract neutral molecules towards each other in gases, liquefied and solidified gases.

Vander waal forces are very weak forces.

Thus, we can conclude that Van der walas interactions are weak interactions would require the least amount of energy to disrupt.

krek1111 [17]3 years ago
3 0

Answer:

Van der waals force

Explanation:

Van der waals force is the weakest and would require less energy to disperse. It’s also known as London forces and mostly found with the halogen groups which undergoes sublimation( solid-gas) change. This force is responsible for this feature.They are usually easily dispersed hence it can also be called dispersion forces

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Elements within the same group of the periodic table behave similarly because they have the same number of ?
sammy [17]
The elements in each group have the same number of electrons in the outer orbital. Or also called valence electrons. Khan academy has a great video online explaining why this happens. (It only happens for main group elements). Here is a link (sorry you can’t click it in Brainly) https://www.khanacademy.org/science/chemistry/periodic-table/copy-of-periodic-table-of-elements/v/periodic-table-valence-electrons. Feel free to message me for a better explanation, I would explain now but I’m not sure how much you know about this. If you know how to write an electron configuration you can see how all the electron configurations for the same group (not the transitional metals only the main groups) have the same number of valence electrons. I hope that helped, sorry I was vague about the explanation :)
4 0
2 years ago
An earthquake's____<br> located directly above its_____
Kipish [7]

Answer:

An earthquake's <u>what happens when two blocks of the earth suddenly slip past one another. </u>

located directly above its <u>The epic Center </u>

Explanation:

<h2>Hope this helps you !! </h2>
6 0
2 years ago
A 0.0372-m3 container is initially evacuated. Then, 4.65 g of water is placed in the container, and, after some time, all of the
Montano1993 [528]

Answer:

18.3 kilopascals

Explanation:

We are given that the volume of this container is 0.0372 meters^3, that the mass of water is 4.65 grams, and that the temperature of this water vapor ( over time ) is 368 degrees Kelvins. This is a problem where the ideal gas law is an " ideal " application.

_______________________________________________________

First calculate the number of moles present in the water ( H2O ). Water has a mass of 18, so it should be that n, in the ideal gas law - PV = nRT, is equal to 4 / 18. It is the amount of the substance.

We now have enough information to solve for P in PV = nRT,

P( 0.0372 ) = 4 / 18( 8.314 )( 368 ),

P ≈ 18,276.9

Pressure ≈ 18.3 kilopascals

<u><em>Hope that helps!</em></u>

5 0
3 years ago
If a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay, what will be the new element?
Charra [1.4K]

Answer:

The new element will be thorium-226 (²²⁶Th).

Explanation:

The beta decay is given by:

^{A}_{Z}X \rightarrow ^{A}_{Z+1}Y + \beta^{-} + \bar{\nu_{e}}

Where:

A: is the mass number

Z: is the number of protons  

β⁻: is a beta particle = electron

\bar{\nu_{e}}: is an antineutrino

The neutral atom has 88 electrons, so:

e^{-} = 88 = Z

Hence the element is radium (Ra), it has A = 226.

If Ra undergoes 2 rounds of beta minus decay, we have:

^{226}_{88}Ra \rightarrow ^{226}_{89}Ac + \beta^{-} + \bar{\nu_{e}}    

^{226}_{89}Ac \rightarrow ^{226}_{90}Th + \beta^{-} + \bar{\nu_{e}}

Therefore, if a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay the new element will be thorium-226 (²²⁶Th).

I hope it helps you!    

8 0
2 years ago
A 38.6 kg marble slab is shown above. What is its density? Give your answer to the nearest tenth.
LuckyWell [14K]

Answer:

Density, d=26.7\ g/cm^3

Explanation:

The attached figure shows a 38.6 kg marble slab. The dimensions of the marble slab is 23 cm × 17 cm × 4 cm

Density = mass/volume

Volume of a cuboid shape is equal to, V = 23 cm × 17 cm × 4 cm

V = 1564 cm³

Density,

d=\dfrac{38.6\times 10^3\ g}{1564\ cm^3}\\\\d=24.68\ g/cm^3

or

d=26.7\ g/cm^3

So, the density of the marble slab is 26.7\ g/cm^3.

6 0
3 years ago
Read 2 more answers
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