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3 years ago

When sulfur dioxide reacts with water droplets in the air, it forms a substance that falls back to earth as _____?

2 answers:

4 0

When sulfur dioxide reacts with water droplets in the air, it forms a substance that falls back to Earth as sulfurous acid.

The equation that rules the transformation is:

SO2 + H2O ---> H2SO3

Sulfurous acid can undergoes further transformation and form sulfuric acid which is what cause the acid rain.

babymother [125]3 years ago

4 0

the answer is

Acid Rain

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How far can a person run in 15 minutes if he or she runs at an average speed of 16 km/hr

Studentka2010 [4]

4 km/hr. There are four quarters in an hour, so just divide 16 by 4 and you get 4. It is directly proportional.

6 0

3 years ago

You are in your car driving on a highway at 23 m/s when you glance in the passenger-side mirror (a convex mirror with radius of

Irina-Kira [14]

Answer:

v = 26. 88 m/s +23 m/s

Explanation:

u = 23 m/s, r = 150 cm, u₁ = 2.0 m/s, s =2.0 m

$\frac{1}{s} +\frac{1}{s'} = \frac{2}{R}$

$\frac{1}{2.0 m} +\frac{1}{s'} = \frac{2}{1.50 m}$

Solve s'

$\frac{1}{s'} = \frac{2}{1.50 m} - \frac{1}{2.0 m}$

$\frac{1}{s'} = 1.833 m$

$s' = - 0.545 m$

To determine the speed of the trick to the highway

$\frac{ds}{dt}= \frac{s^2* \frac{ds}{dt}}{s' ^2} =\frac{2.0 ^2m * 2.0 m/s}{0.545^2m}$

$\frac{ds}{dt} = 26.88 m/s$

Now to determine the velocity highway is going to be

v = ds/dt + u

v = 26. 88 m/s +23 m/s

8 0

3 years ago

A force AB of length 100m and weight 600N has its centre of gravity 4.0 m from the end, and lies on horizontal ground calculate

Stells [14]

Answer:

F = 24 N

Explanation:

In this exercise we have a bar l = 100 m with a center of gravity x = 4 m, which force is needed to lift it from the other end

Let's use the rotational equilibrium relationship, where we consider the counterclockwise rotations as positive and fix the reference system at the point closest to the center of gravity

∑ τ = 0

F l -x W = 0

F = $\frac{x}{l} \ W$

let's calculate

F = $\frac{4}{100}$ 4/100 600

F = 24 N

8 0

3 years ago

Accomplished silver workers in india can pound silver into incredibly thin sheets, as thin as 3.00 10-7 m (about one-hundredth o

postnew [5]

The density of silver is ρ = 10500 kg/m³ approximately.

Given:
m = 1.70 kg, the mass of silver
t = 3.0 x 10⁻⁷ m, the thickness of the sheet

Let A be the area.
Then, by definition,
m = (t*A)*ρ

Therefore
A = m/(t*ρ)
= (1.7 kg)/ [(3.0 x 10⁻⁷ m)*(10500 kg/m³)]
= 539.7 m²

Answer: 539.7 m²

8 0

3 years ago

At which location would an objects weight be the greatest. 1.pluto 2.earth 3.sun 4.moon

Maslowich

Weight of the object is given as

$Weight = mg$

so weight of the object will be maximum where gravity(g) will be maximum

so here out of all given four the gravity "g" will be maximum at the surface of SUN as we know that sun will be of maximum mass out of all four planets

as we know that

$g = \frac{GM}{R^2}$

so correct answer will be

3. SUN

8 0

4 years ago

Read 2 more answers