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SpyIntel [72]
3 years ago
14

In reaching her destination, a backpacker walks with an average velocity of 1.20 m/s, due west. This average velocity results, b

ecause she hikes for 5.63 km with an average velocity of 2.33 m/s due west, turns around, and hikes with an average velocity of 0.374 m/s due east. How far east did she walk (in kilometers)?
Physics
1 answer:
GaryK [48]3 years ago
7 0

Answer:

x_2 = 648.46\ m

Explanation:

given,

Average velocity due west =  1.20 m/s

case 1

Distance moved in west, x₁ = 5.63 km

speed due west, v₁ = 2.33 m/s

Case 2

Distance moved in east = x₂

speed due east, v₂ = 0.374 m/s

total distance = x₁ + x₂ = 5.62

total time = t₁ + t₂ = 5630/2.33 + x₂/0.374

now,

average\ velocity = \dfrac{total\ distance}{total\ time}

-1.20= \dfrac{-5630 + x_2}{\dfrac{5630}{2.33}+\dfrac{x_2}{0.374}}

negative sign is used because we want the distance in east but velocity is in west.

- 2900 - 3.21 x_2 = -5630 + x_2

-4.21 x_2 = -2730

x_2 = 648.46\ m

The distance she walked in east is equal to 648.46 m

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An airliner arrives at the terminal, and its engines are shut off. The rotor of one of the engines has an initial clockwise angu
Ilia_Sergeevich [38]

(a) 1200 rad/s

The angular acceleration of the rotor is given by:

\alpha = \frac{\omega_f - \omega_i}{t}

where we have

\alpha = -80.0 rad/s^2 is the angular acceleration (negative since the rotor is slowing down)

\omega_f is the final angular speed

\omega_i = 2000 rad/s is the initial angular speed

t = 10.0 s is the time interval

Solving for \omega_f, we find the final angular speed after 10.0 s:

\omega_f = \omega_i + \alpha t = 2000 rad/s + (-80.0 rad/s^2)(10.0 s)=1200 rad/s

(b) 25 s

We can calculate the time needed for the rotor to come to rest, by using again the same formula:

\alpha = \frac{\omega_f - \omega_i}{t}

If we re-arrange it for t, we get:

t = \frac{\omega_f - \omega_i}{\alpha}

where here we have

\omega_i = 2000 rad/s is the initial angular speed

\omega_f=0 is the final angular speed

\alpha = -80.0 rad/s^2 is the angular acceleration

Solving the equation,

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6 0
3 years ago
A small but measurable current of 3.8 × 10-10 A exists in a copper wire whose diameter is 2.5 mm. The number of charge carriers
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Answer:

a) 4.9*10^-6

b) 5.71*10^-15

Explanation:

Given

current, I = 3.8*10^-10A

Diameter, D = 2.5mm

n = 8.49*10^28

The equation for current density and speed drift is

J = I/A = (ne) Vd

A = πD²/4

A = π*0.0025²/4

A = π*6.25*10^-6/4

A = 4.9*10^-6

Now,

J = I/A

J = 3.8*10^-10/4.9*10^-6

J = 7.76*10^-5

Electron drift speed is

J = (ne) Vd

Vd = J/(ne)

Vd = 7.76*10^-5/(8.49*10^28)*(1.60*10^-19)

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Vd = 5.71*10^-15

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3 0
3 years ago
10th grade Physical Science.... Help plss
Alekssandra [29.7K]

1) A negatively charged ion is chloride

2) Moving from left to right, valence electrons increase by one.

3) The period number gives information about how many energy levels it has

4) Fluorine has a charge of 1–

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The periodic table is an arrangement of elements into groups and periods based on their periodic properties.

In the periodic table, elements are arranged in groups and periods. There are 18 groups and 8 periods.

Chlorine is in group 17, there have seven outermost electrons hence the chlorine atom needs only one more electron in order to attain a stable octet. This is done by accepting one electron to form the negatively charged chloride ion.

As we move from one period to another, one extra electron is added to the outermost shell of elements. Hence, the valence electrons increases by one.

The period to which an element belongs shows you the number of shells or energy levels in the atom of that element.

Fluorine is in group 17. One electron is needed to achieve a stable octet. When an atom accepts one electron, its charge is 1–.

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