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QveST [7]
4 years ago
5

The surface layer of the sun, just below the chromosphere

Physics
1 answer:
serious [3.7K]4 years ago
5 0
Just below the chromosphere, is the photosphere.

Hope this helped!  
You might be interested in
Which organisms play roles similar to organisms in water ecosystem
lina2011 [118]
Is there a multiple choice?
4 0
4 years ago
A block with a mass of 31.8 kg is pushed on a frictionless
OlgaM077 [116]

Answer: Total work done on the block is 3670.5 Joules.

Step by step:

Work done:

W = F.d.\cos\theta

With F the force, d the displacement, and theta the angle of action (which is 0 since the block is pushed along the direction of displacement, and cos 0 = 1)

W = F.d

Given:

F = 75 N

m = 31.8 kg

Final velocity v_f = 15.3 \frac{m}{s}

In order to calculate the Work we need to determine the displacement, or distance the block travels. We can use the information about F and m to first figure out the acceleration:

F = ma\\\implies a=\frac{F}{m}=\frac{75 N }{31.8 kg}\approx 2.36 \frac{m}{s^2}\\

Now we can determine the displacement from the following formula:

d = \frac{1}{2}a^2+v_0t+d_0

Here, the initial displacement is 0 and initial velocity is also 0 (at rest):

d = \frac{1}{2}at^2\\

Now we still have "t" as unknown. But we are given one more bit of information from which this can be determined:

v_f = a\cdot t_f\\\implies t_f = \frac{v_f}{a} = \frac{15.2 \frac{m}{s}}{2.36 \frac{m}{s^2}}\approx 6.44 s

(using vf as final velocity, and tf as final time)

So it takes about 6.44 seconds for the block to move. This allows us to finally calculate the displacement:

d = \frac{1}{2}at^2=\frac{1}{2}2.36 \frac{m}{s^2}\cdot 6.44^2 s^2 \approx 48.94 m

and the corresponding work:

W = F\cdot d=75 N\cdot 48.94 m =3670.5J


7 0
3 years ago
Five equal negative charges are uniformly spaced in a semicircular
balu736 [363]

Answer:

The direction is that of a 3rd quadrant angle

Explanation:

when you have 2 45 angles it equals to 90 then with the 90 we multiply by 2 due to the 2 adjacent angles equating to 180 which swings it to the 3rd quadrant angle

6 0
4 years ago
You make a telephone call from New York to a friend in London. Estimate how long it will take the electrical signal generated by
nadezda [96]

Answer:

a)  t = 2 10⁻² s ,  t = 2.4 10-1 s

Explanation:

In this exercise they indicate the delay in two signals

a) A signal travels on an electrical cable, between New York and London.

The wave formed in this wire for the signal. This wave travels at the speed of light, c = 3 108 m / s, so the delay is very small

                t = d / c

               t = 6000 10³/3 10⁸

               t = 2 10⁻² s

b) The signal points to a satellite in geostationary orbit

                   distance traveled = √ (2 36000 10³)² + 6000²

                  distance = 72 10⁶ m

the waiting time is

                t = d / c

                t = 72 10⁶/3 10⁸

               t = 2.4 10-1 s

    we can see that the signal sent by the satellites has more delay because its distance is much greater

8 0
3 years ago
The bar ab has a velocity at point a of va = [20,9] m/s and an angular velocity w = 23 rad/s. If the distance between a and b is
DiKsa [7]

speed of point A is given as

v_a = 20.9 m/s

v_a = r*\omega

here r = distance from the axis

so here we have

20.9 = r*23

r  = 0.91 m

now the distance of point A and B is 0.71 m

while the distance of axis from point A is 0.91 m

so distance of axis from point B will be given as

r = 0.91 + 0.71 = 1.62 m

now for the speed of point b is given as

v = r \omega

v = 1.62 * 23

v = 37.26 m/s

so end point B will move with speed 37.26 m/s

8 0
3 years ago
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