Because they both have a nucleus but both of them do not have a cell wall
Answer:
<h2>i) C-1
</h2><h2>ii) C-3
</h2><h2>iii) C-3
</h2><h2>iv) C-2 (methyl group)
</h2><h2>v) C-4
</h2><h2>vi) C-4
</h2><h2>vii) Equally distributed in C-2 and C-3.</h2>
Explanation:
i) In Fructose-1,6-bisphosphate
, initial incorporation of 14^C occurs at C-1
ii) In Glyceraldehyde-3-phosphate, initial incorporation of 14^C occurs at C-3
iii) In Phosphoenolpyruvate, initial incorporation of 14^C occurs at C-3
iv) In Acetyl-CoA, initial incorporation of 14^C occurs at C-2 (methyl group)
v) In Citrate, initial incorporation of 14^C occurs at C-4
vi) In a-ketoglutarate, initial incorporation of 14^C occurs at C-4
vii) in Oxaloacetate, initial incorporation of 14^C occurs at Equally distributed in C-2 and C-3.
If i remember correctly they should be adenine (A), thymine (T), guanine (G) and cytosine (C). i hope this helps. sorry if they arent all correct.
The nurse can give the following instructions:
1. the procedure will most likely last for ten minutes
2. since it is still an infant, the child will be put under anaesthesia
3. a pulsed dye laser treatment will be given
4. if general anaesthesia will be given, then there are special rules for eating and drinking restrictions before procedure
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