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3 years ago

How do i solve? 2/3h = -9

Mathematics

2 answers:

TEA [102]3 years ago

6 0

I think it is right how i did it but i got -3
yeah

kkurt [141]3 years ago

3 0

3h × 2 / 3h = -9 × 3h

therefore

2 = -27h

h = -27/ 2

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Answer:

AB=7.21 unit

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CD=7.21 unit

AD= 6 unit

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Step-by-step explanation:

Coordinates of A =(-2,3)

Coordinates of B = (2,-3)

Coordinates of C = (2,3)

Coordinates of D =(-2,-3)

Distance formula : $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$A=(x_1,y_1)=(-2,3)\\B=(x_2,y_2)=(2,-3)\\AB = \sqrt{(2+2)^2+(-3-3)^2}$

AB=7.21 unit

$B=(x_1,y_1)=(2,-3)\\C=(x_2,y_2)=(2,3)\\BC=\sqrt{(2-2)^2+(3+3)^2}$

BC=6

$C=(x_1,y_1)=(2,3)\\D=(x_2,y_2)=(-2,-3)\\CD=\sqrt{(-2-2)^2+(-3-3)^2}$

CD=7.21

$A=(x_1,y_1)=(-2,3)\\D=(x_2,y_2)=(-2,-3)\\AD=\sqrt{(-2+2)^2+(-3-3)^2}$

AD=6

$A=(x_1,y_1)=(-2,3)\\C=(x_2,y_2)=(2,3)$

$AC=\sqrt{(2+2)^2+(3-3)^2}$

AC=4

$B=(x_1,y_1)=(2,-3)\\D=(x_2,y_2)=(-2,-3)$

BD= $\sqrt{(-2-2)^2+(-3+3)^2}$

BD=4

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