Answer:
164+3.28
Step-by-step explanation:
(16.4)(10)+(16.4)(0.2)
164+3.28
167.28
Answer:
Step-by-step explanation:
The prices of quoted of auto repairs are as listed below;
$139, $150, $345, $99, $167, $155, $140, $200.
For her to check whether there is an outlier in the data, she needs to find the mean of the set of data. An outlier is a value in a set of a data that varies considerably from other data in a dataset. It may be larger or smaller than other set of datas. An outlier can affect the decision of a set of data to be analysed if nor taken care of.
From the data, the possible outliers are $99 and $345
Mean of the data = sum of all the prices/sample size
xbar = \sum Xi / N
Xi are individual datas
\sum Xi = $139+$150+$345+$99+$167+$155+$140+$200+$160
\sumXi = $1555
Sample size = 9
Mean = $1555/9
Mean = $172.78
Hence the value that would best represent the central tendency is $177.78
Answer:
<em>AB = 5√2</em>
<em>AC = √145</em>
<em>BC = √65</em>
Step-by-step explanation:
Using the formula for calculating the distance between two points
D = √(x2-x1)²+(y2-y1)²
For AB A(-3,6),B(2,1),
AB = √(2+3)²+(1-6)²
AB = √(5)²+(-5)²
AB = √25+25
AB = √50
<em>AB = 5√2</em>
For AC A(-3,6) and C(9,5)
AC = √(9+3)²+(5-6)²
AC = √(12)²+(-1)²
AC = √144+1
<em>AC = √145</em>
For BC B(2,1), and C(9,5)
BC = √(9-2)²+(5-1)²
BC = √(7)²+(4)²
BC = √49+16
<em>BC = √65</em>
<em></em>
<em>Since All the sides are difference, hence triangle ABC is a scalene triangle</em>
Best Answer:<span> </span><span>694 m = 0.694 km
1hr = 3600 s
3600 × 0.694 = 2498.4 km/h</span>
Answer:
- 15 - 7 (Parentheses)
- 3² (Exponents)
- 8 × 2 (Multiplication)
- 40 ÷ 8 (Division)
- 5 + 9 (Addition starting from the leftmost)
- 14 + 16 (Addition after the first addition operation)
Concept:
When encountering questions that ask for simplifying expressions through operation, following the PEMDAS method would be easier:
- <u>P</u>arentheses
- <u>E</u>xponents
- <u>M</u>ultiplication
- <u>D</u>ivision
- <u>A</u>ddition
- <u>S</u>ubtraction
Therefore, the whole process of simplifying the given expression should follow the PEMDAS method. <u>For extra</u>, whenever there are two occurences of the same operation, then prioritize the leftmost and go right.
Hope this helps!! :)
Please let me know if you have any questions or need further explanation
