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Inessa [10]
4 years ago
9

In solving a physics problem you end up with m in the numerator and m/s in the denominator. The units for your answer are :_____

__
Physics
1 answer:
Vladimir [108]4 years ago
7 0

Answer:

s

Explanation:

It is given that, a physics problem you end up with m in the numerator and m/s in the denominator. It would mean that,

\dfrac{\text{numerator}}{\text{denominator}}=\dfrac{m}{m/s}

m is metre and s is second

or

=\dfrac{m}{\dfrac{m}{s}}\\\\=\dfrac{s}{1}

so, the unit of the answer is <u>s</u>.

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A plumber heats a plastic pipe, softens it, shapes it, and then lets it cool. After it is hardened, the
aev [14]

Answer:

thermoset

Explanation:

A thermoset material is a polymer that is irreversibly hardened by curing. Curing is induced by heat and cannot be undone because the polymers cross link during the process, creating permanent chemical bonds.

3 0
3 years ago
A manometer that is filled with water (rho=1000 kg/m3) is connected to a wind tunnel to measure the pressure inside the test sec
Anna [14]

To develop this problem it is necessary to apply the concepts performed to the absolute pressure based on the reference pressure (atmospheric) and the pressure that is generated due to the height of the column of the measured liquid.

In mathematical terms the previous concept can be expressed as

P_{abs} = P_{atm} -\rho gh

Where

P_{atm}=Atmospheric Pressure

\rho =Density

g = Gravitational acceleration

h = Height

Our values are given as

h = 10*10^{-3}m

g = 9.8m/s

\rho_{water} = 1000kg/m^3

P_{atm} = 100kPa

Replacing we have then that

P_{abs} = P_{atm} -\rho gh

P_{abs} = 100 -(1000)(9.8)(10*10^{-3})

P_{abs} = 99.9019kPa

Therefore the absolute pressure in the test section is 99.9019kPa

6 0
3 years ago
Explain the relationship between speed and steepness of the slope of the line on the distance-versus-time graph
balandron [24]

Explanation:

A distance-versus-time graph gives the distance an object has traveled after a given time.

In a distance-versus-time graph the slope represents the the speed of the object because rise/run is

  \frac{\Delta distance }{\Delta time}=speed.

And how steep the slope of the distance-versus-time graph is tells us how fast an object is moving; steeper the slope greater the speed. For example, a graph with slope 10 represents a greater speed than a graph with slope 2.

So the steepness of the slope of the distance-versus-time is the speed of the object, and greater the slope greater is the speed.

6 0
3 years ago
How do i calculate this?
Lesechka [4]

CAR 1

Momentum = Mass/Velocity

M = 2100/20

M = 105 m/s^2

CAR 2

Momentum = Mass/Velocity

M = 2100/30

M = 70 m/s^2

8 0
3 years ago
A box is moved 20 m across a smooth floor by a force making a downward angle with the floor, so that there is effectively a 10 N
Usimov [2.4K]

Answer:

100 J

Explanation:

From the question, The work done by the forces in moving the box is given as

W = FxdcosФ+Fydcosα................... Equation 1

Where W = Work done, Fx = force acting parallel to the floor, d = distance moved by the box, Ф = angle the parallel force makes with the floor, Fy = force acting perpendicular to the floor, α = angle the perpendicular force make with the floor.

Give: Fx = 10 N, d = 20 m, Fy = 5 N, Ф = 0°, α = 90°

Substitute into equation 1

W = 10×10×cos0°+5×20×cos90°

W = 10×10×1+0

W = 100 J.

Note: The work done by the perpendicular force is zero

Hence the work done = 100 J

5 0
3 years ago
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