Ba(NO₃)₂ + Na₂SO₄ → BaSO₄ + NaNO₃
By Trial and error.
Ba(NO₃)₂ + Na₂SO₄ → BaSO₄ + 2NaNO₃
Check:
LHS RHS
Ba 1 1
N 2 2
S 1 1
O 3*2 + 4 = 10 4 + 2*3 = 10
The total kinetic energy of the system after collision is 223.5J
In elastic collision kinetic energy and momentum are conserved.
According to the question
mass of object a = 25kg
mass of object b = 25 kg
initial velocity of a u1 = 5.98 m/s
initial velocity of b u2 = 0
so from momentum conservation-
mau1 + mbu2 = (m1+m2)v
25kg × 5.98m/s + 25×0 = (25+25)v
v = 2.99 m/s
Now the total kinetic energy after the collision will be:
final kinetic energy = 1/2 (m1+m2) v²
= 1/2 (25+25)× (2.99)²
= 223.5 J
Thus, total kinetic energy of the system after collision is 223.5J
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The value that should be reported for the total mass of three samples of iron will be 0.143 Kg or 143 g
<h3>
What is Mass and Weight ?</h3>
Mass is the quantity of matter. While weight is a gravitational pull on an object. Mass is measured in Kg while weight is measured in Newton.
What value should be reported for the total mass of three samples of iron weighing 117.0 g, 19.43 g, and 6.1043 g?
The total mass will be the sum of the three masses.
The total mass = 117 + 19.43 + 6.1043
The total mass = 142.5343 g
Convert gram to kilogram by dividing the answer by 1000
The total mass = 142.5343/1000
The total mass = 0.1425343 Kg
Therefore, the value that should be reported for the total mass of three samples of iron will be 0.143 Kg or 143 g approximately
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the plane is on a average of 100km a hour
Answer:
Explanation:
Let the radius of track required be r.
Centripetal force will be provided by frictional force which will be equal to
m v²/ r
Frictional force = mg x μ
So
m v² /r = mg μ
r = v² / μ g =
v = 29 km /h = 8.05 m /s
r =( 8.05 x 8.05 ) /( .32 x 9.8 ) = 20.66 m
