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mr Goodwill [35]
3 years ago
15

Compared to yellow light,orange light has

Physics
1 answer:
ArbitrLikvidat [17]3 years ago
5 0
<span>So we wonder how can we compare yellow and orange light. Light is a small art of electromagnetic spectrum which is a continuum of all electromagnetic waves arranged by wavelenght and frequency. So on the EM spectrum orange has greaterr wavelangth than yellow but smaller frequency because wavelength and frequency are connected by the equation: c=f*lambda, where lambda is the wavelength and c is the speed of light and f is the frequency. We see that the higher the frequency the smaller the wavelength and vice versa.</span>
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This version of Einstein’s equation is often used directly to find what value?
Setler [38]
This version of Einstein’s equation is often used directly to find what value? E = ∆mc2

Answer: This version of Einstein’s equation is often used directly to find the mass that is lost in a fusion reaction. Therefore the correct answer to this question is answer choice C).

I hope it helps, Regards.
8 0
3 years ago
Read 2 more answers
A crate filled with delicious junk food rests on a horizontal floor. Only gravity and the support force of the floor act on it,
stealth61 [152]

The words "... as shown ..." tell us that there's a picture that goes along
with this question, and you decided not to share it.  That's sad and
disappointing, but I think the question can be answered without seeing
the picture.

The net force on the crate is zero.  Evidence for this is that fact that
the crate is just sitting there.  If the net force on an object is not zero,
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4 0
3 years ago
7. Imagine you are pushing a 15 kg cart full of 25 kg of bottled water up a 10o ramp. If the coefficient of friction is 0.02, wh
pentagon [3]

Answer:

The frictional force needed to overcome the cart is 4.83N

Explanation:

The frictional force can be obtained using the following formula:

F= \mu R

where \mu is the coefficient of friction = 0.02

R = Normal reaction of the load = mgcos\theta = 25 \times 9.81 \times cos 10 = 241.52N

Now that we have the necessary parameters that we can place into the equation, we can now go ahead and make our substitutions, to get the value of F.

F=0.02 \times 241.52N

F = 4.83 N

Hence, the frictional force needed to overcome the cart is 4.83N

4 0
3 years ago
Can i get help for the parts for the two questions? MATHPHYSSSS
Anestetic [448]

Explanation:

003 (part 1 of 2)

Pressure is force divided by area.

P = F / A

P = (117 kg × 9.8 m/s²) / (2 × (0.05 m)²)

P = 229,320 Pa

003 (part 2 of 2)

There are approximately 6895 Pa in 1 psi.

P = 229,320 Pa × (1 psi / 6895 Pa)

P = 33.3 psi

004 (part 1 of 2)

Since the collisions are elastic, the angle of reflection is the same as the angle of incidence (it bounces off at the same angle).

Impulse = change in momentum

F Δt = m Δv

F (36 s) = (300 × 0.003 kg) (5.2 sin 57° m/s − (-5.2 sin 57° m/s))

F = 0.218 N

004 (part 2 of 2)

Pressure is force over area.

P = F / A

P = 0.218 N / 0.712 m²

P = 0.306 N/m²

7 0
3 years ago
During a blackout, you are trapped in a tall building. you want to call rescuers on your cell phone, but you can't remember whic
Gennadij [26K]

Let the height where we are trapped is H

now to find the time to reach the key at the bottom is given as

y = v_i t + \frac{1}{2}at^2

now we have

H = \frac{1}{2}gt^2

t = \sqrt{\frac{2H}{g}}

now if the speed of sound is considered to be 340 m/s then time taken by the sound to reach at the top is given as

t = \frac{H}{340}

now the total time is given as

\sqrt{\frac{2H}{g}} + \frac{H}{340} = 3.27

now by solving above equation we have

H = 48 m

now height of one floor is 3 m

so our position must be

N = \frac{48}{3} = 16 th \:floor

3 0
3 years ago
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