Answer:
1) 1) 97 – 39. It becomes
100 - 40 = 60
2)2) 812,344 – 187,675. It becomes
800000 - 200000 = 600000
3)321 + 79. It becomes
300 + 80 = 410
4) 315 x 821. It becomes
300 + 800 = 1100
5) 562 x 791. It becomes
600× 800 = 480000
6) 82 x 156. It becomes
80×200 = 16000
7) 711 x 884. It becomes
700×900 = 630000
8) 126 x 952. It becomes
100×1000 = 100000
9) 824 x 541. It becomes
800× 500 = 400000
10) 4027 x 78. It becomes
4000×80 = 320000
11) 796 x 123. It becomes
800×100 = 80000
12) 817 19. It becomes
800/20 = 40
13) 3615 72. It becomes
4000/70 = 57.1 = 60
14) 232 64. It becomes
200/60 = 33.3 = 30
15) 559 81. It becomes
600/80 = 7.5 = 8
16) 2986 222. It becomes
3000/200 = 15
17) 10275 232. It becomes
10000/200 = 50
18) 7428 286. It becomes
7000/300 = 23.3 = 20
19) 7143 369. It becomes
7000/400 = 17.5 = 18
20) 628,597 1525, it becomes
600000 - 2000 = 300
Step-by-step explanation:
Answer:
none of the choices is correct
Step-by-step explanation:
To find the length of the side of square 1, divide the perimeter, 104÷4 = 27
That is the hypotenuse of the triangle.
The square of 27 is 729
Subtract the given square of Square 2, 576
729 - 576 = 153
Take the square root of 153 to find the length of the side of Square 3
√153= 12.37
I hope this helps. It's just a bit more challenging version of Pythagorean Theorem: a² + b² = c²
Jacob wants to build a rectangular enclosure for his animals. One side of the pen will be against the barn,so he needs no fence on that side.
Let w be the width of the enclosure (perpendicular to the barn) and let l be the length of the enclosure (parallel to the barn).
one side of the length is not counted for perimeter because one side of length will be against the barn.
Perimeter = 400 ft
Perimeter of rectangle = L + W + W
400 = L + 2W
L = 400 - 2W
Area = L * W
Replace L by 400 - 2W
A(W) = (400 - 2W) * W
Now we find out x coordinate of vertex to find the width that maximize the area
a= -2 and b = 400
The width w would maximize the area is w = 100ft
To find maximum area we plug in 100 for W in A(W)
the maximum area is 20,000 square feet
