I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
---------------------
So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
---------------------
<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
Answer:
Option A) y=1000(1.15)^6 2313 bacteria
Step-by-step explanation:
The initial value is 1,000 and the growth factor would be the the 15%.
15% can be rewritten to .15, but you have to have to add 1 for the start to make the equation easier. Thus making the growth factor 1.15
After multiplying 1000(1.15)^6 you will get 2313.06076562 which is simplified to 2,313 bacteria.
Hope this is helpful. :)
Answer: The r<span>-value for the linear function related to the ordered pairs is very close to zero, so it is not a good representation of the data. A quadratic model would better represent the data because there is a turning point within the data set. The data increases then decreases, which is what the graph of a quadratic does. </span>
