Answer:
7.92 .g . mL^-1
Explanation:
Data provided in the question
Water liters = 45.5 mL
Pace of iron = 28.5 gram
Rise in the water in the cylinder = 49.1 mark
So by considering the above information
As we know that
where,
Mass = 28.5 gram
Volume = 49.1 - 45.5
= 3.6 mL
So, the density is
= 7.92 .g . mL^-1
Basically we use the density formula by dividing the mass with the volume
Answer:
1.06 atm
Explanation:
We are given the following variables to work with:
Initial pressure (P1): unknown
Initial temperature (T1): 348 K
Final temperature (T2): 506 K
Final pressure (P2): 1.55 atm
We are asked to find the initial pressure (P1). We want to choose a gas law equation that relates initial pressure and temperature to final pressure and temperature. Gay-Lussac's law does this:
We can rearrange the law algebraically to solve for .
Substitute your known variables and solve: