Name 5 Scientific types of systems IF YOU PUT A REASONABLE ANSWER, I WILL MARK YOU BRAINLEST

1 answer:

5 0

Open system ( exchanges energy and matter with the surroundings)
Closed system ( exchanges only energy with the surroundings)
Isolated system ( does not exchange energy or matter)
Adiabatic system ( does not allow any heat to be transferred into or out of the system)

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Looking at the car in the picture above, explain how the electrons act to form this compound that is on the surface of the car,

dmitriy555 [2]

Answer:

The correct answer is "Iron and oxygen act as Fe3+ and O2− ions respectively, forming rust (Fe₂O₃) in the presence of water by the formation of an ionic bond".

Explanation:

Rust is formed when iron reacts with oxygen in the presence of water (either if the iron is submerged or exposed to moisture in the air), forming the chemical compound Fe₂O₃. The presence of water is needed for rust formation because iron and oxygen act as ions when they are exposed to water, particularly Fe3+ and O2− ions respectively. The bond formed between these two elements are ionic bonds, because it is comprised of the reaction between a metal (iron) and a non-metal (oxygen).

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¿Podría predecir con antelación si una disolución acuosa será buena conductora de la corriente eléctrica, sabiendo cuál es el so

Ne4ueva [31]

Answer:

Si.

Explicación:

Sí, podemos predecir si una solución acuosa será un buen conductor de corriente eléctrica si conocemos el soluto que se disuelve en ese líquido y su concentración o cantidad. Hay algunas sustancias que se ionizan cuando se agregan en un líquido como el agua. Debido a esta ionización, será un buen conductor de electricidad. Por ejemplo, la adición de una gran cantidad de cloruro de sodio en agua ioniza y hace que el agua sea un buen medio conductor de electricidad.

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RATE LAW QUESTION !

vivado [14]

In general, we have this rate law express.:

$\mathrm{Rate} = k \cdot [A]^x [B]^y$
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4) by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation $\Delta \mathrm{Rate} = \Delta [B]^y$

$3.09 = (3)^y \implies y \approx 1$

To this point, $\mathrm{Rate} = k \cdot [A]^x [B]^1$

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for $\Delta \mathrm{Rate} = \Delta [A]^x$

$4= (2)^x \implies x = 2$

the rate law is

Rate = k·[A]²[B]

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Answer:

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julsineya [31]

Answer :The element cobalt is characterzied by the presence of 27 massive, positively charged particles, 27 protons , in its nucleus. Since it is 58Co , there are 31 neutrons , 31 massive, neutrally charged particles in its nucleus.

Explanation:

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