A. If B is a basis for a subspace H, then each vector in H can be written in only one way as a linear combination of the vectors
1 answer:
You might be interested in
Since 12 is 8 x 1 1/2 she needs 1 1/2 time as much fruit.
1 1/2 x 10 = 15 strawberries and 1 1/2 x 4 = 6 oranges.
You could also solve this using proportions:
Cross multiply and get 8n= 120 divide by 8 and get 15 strawberries
Do the same for the oranges:
You can see that 4/8 = 1/2 so n/12 has to be 6 to be 1/2 (or solve it using cross products like I did above).
1 1/2 x 10 = 15 strawberries and 1 1/2 x 4 = 6 oranges.
You could also solve this using proportions:
Cross multiply and get 8n= 120 divide by 8 and get 15 strawberries
Do the same for the oranges:
You can see that 4/8 = 1/2 so n/12 has to be 6 to be 1/2 (or solve it using cross products like I did above).
Probability of an adult who needs correction = 82% or 0.82
So, probability of an adult who does not needs correction = 1 - 0.82 = 0.18
If 12 adults are randomly selected, the probability that at least 11 of them need correction for their eyesight is:
12C11 + 12C12
= 12*0.11*0.18 + 1*0.09*1
= 0.238+0.09
= 0.328 or 0.33
And, yes, 11 is significantly a high number of adults requiring eyesight correction.