We have to simplify
sec(θ) sin(θ) cot(θ)
Now first of all let's simplify these separately , using reciprocal identities.
Sec(θ) = 1/cos(θ)
Sin(θ) is already simplified
Cot(θ)= cos(θ) / sin(θ) ,
Let's plug these values in the expression
sec(θ) sin(θ) cot(θ)
= ( 1/cos(θ) ) * ( sin(θ) ) * ( cos(θ) / sin(θ) )
= ( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
sin cancels out with sin and cos cancels out with cos
So , answer comes out to be
=( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
= 1
244
The 4's are in the ONE's and TEN's places
Ok to solve this just write it out how it sounds, like so.
3x/4
-16
Hope this helps!=)
It would be D. because the volume of a sphere is 4/2 x pi x radius^3.
Answer:
We have sinθ = 12/13
The method here is to figure out the value of θ
Using a calculator sin^(-1)(12/13) =67.38°
67.38° is in quadrant 1 so we must substract 67.38° from 180° wich is π
- 180-67.38= 112.61° ⇒ θ= 112.61°
Now time to calculate cos2θ and cosθ using a calculator
- cosθ = -5/13
- cos2θ = -0.7
The values we got make sense since θ is in quadrant 2 and 2θ in quadrant 3
