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xxMikexx [17]
4 years ago
13

1s2 2s2 2p6 3s2 3p6 is the electron configuration for

Chemistry
2 answers:
faltersainse [42]4 years ago
4 0

Answer: Argon (Ar)

Explanation:

The reason why it is Argon is because when you add the electrons 2+2+6+2+6, there will be 18 electrons total and the number 18 is also from the atomic number. I just learned this a while ago and remembered how to do it since you need help with this. I hope this helps and have a good day!

kvasek [131]4 years ago
3 0

Answer: The electron configuration is for the element Argon

Explanation: 3p6 is all the way on the right side of the periodic table in the third row or period

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Part A: How many moles of NH3 can be produced from 21.0 mol of H2 and excess N2?
Lorico [155]

Answer:

a) 7.0 moles of NH3

b) 61.2 g of NH3

c) 4.15 g of H2

d) 8.9 ×10^19 molecules

Explanation:

Equation of the reaction;

N2(g) + 3H2(g) ⇄NH3(g)

a)

If 3 moles of H2 yields 1 mole of NH3

21 moles of H2 will yield 21 × 1 /3 = 7.0 moles of NH3

b)

1 mole of N2 yields 17 g of NH3

3.6 moles of N2 yields 3.6 moles × 17 g of NH3 = 61.2 g of NH3

c)

If 6g of H2 produces 17 g of NH3

xg of H2 will produce 11.76 g of NH3

x= 6 × 11.76/17

x= 4.15 g of H2

d)

If 6g of hydrogen yields 6.02 × 10^23 molecules of NH3

8.86 × 10^-4g of H2 yields 8.86 × 10^-4g × 6.02 × 10^23 /6 = 8.9 ×10^19 molecules

8 0
4 years ago
For the following galvanic cell, represented in line notation, determine what balanced half-reactions occur at each electrode. (
Alex787 [66]

Answer:

Anode (oxidation): Cr(s) ⇒ Cr³⁺(aq) + 3 e⁻

Cathode (reduction): Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)

Explanation:

Let's consider the notation of a galvanic cell.

Cr(s) | Cr³⁺(aq) || Ag⁺(aq) | Ag(s)

On the left, it is represented the anode (oxidation) and on the right, it is represented the cathode (reduction).

The half-reactions are:

Anode (oxidation): Cr(s) ⇒ Cr³⁺(aq) + 3 e⁻

Cathode (reduction): Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)

To have the global reaction, we have to multiply the reduction by 3 (so the number of electrons gained and lost are the same) and add both half-reactions.

Global reaction: Cr(s) + 3 Ag⁺(aq) ⇒ Cr³⁺(aq) + 3 Ag(s)

6 0
3 years ago
Catalase is an enzyme that speeds up the breakdown of hydrogen peroxide in cells. During this reaction oxygen is given off. A sc
Softa [21]

Answer:

The correct option is A

Explanation:

An independent variable is <u>a variable that is intentionally altered (directly or indirectly) and is not dependent on another variable</u> in the course of an experiment. Unlike the independent variable, the dependent variable depends or is presumed to depend on the altered independent variables.

From the explanation above, it can be deduced that the concentration of the catalase is the independent variable as it was intentionally altered (by using different concentrations) in the course of the experiment. The amount of oxygen given off is the dependent variable here

6 0
3 years ago
In the lab, you mix two solutions (each originally at the same temperature) and the temperature of the resulting solution decrea
Archy [21]

Answer:

The correct answer is option B.

Explanation:

Endothermic reactions are defined as the reactions in which energy of products is more than the energy of the reactants. In these reactions, energy is absorbed by the system.

The total enthalpy of the reaction (\Delta H) comes out to be positive.

Exothermic reactions are defined as the reactions in which energy of reactants is more than the energy of the products. In these reactions, energy is released by the system.

The total enthalpy of the reaction (\Delta H) comes out to be negative.

On mixing of both solution we had observed that temperature of the resulting solution was lowered this is because the energy was absorbed during the chemical reaction.

4 0
4 years ago
A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the stu
vlabodo [156]

Answer is 30.0mL

according to the question dilution is performed by the student which can be calculated with the help of :

                          M_{1}V_{1}=M_{2}V_{2}     EQUATION (1)


Here, we have:

 M_{1} = 3M

  V_{1}  = y mL

M_{2}= 1.80 M

V_{2} = 50.0mL

putting the known values in equation (1) which will give us value of V_{1}

                                         3.00× y =1.80 ×50.0

                                                         y= 30.0mL

3 0
4 years ago
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