KCl: 74.5g/mol
Molarity = mol/Liters
Since you are given 0.750L and 1.50M, we can plug it into the molarity formula and solve for moles.
1.50M = x mol/0.750L
X = 1.125 moles of KCl needed
You asked for grams so let’s convert the moles of KCl to grams:
1.125 mol x (74.5g/mol) = 83.8g KCl
53.5 g MgCl2 /95.21 g/mol = 0.5619 Moles MgCl2. Since the ratio is 3MgCl : 2Na3PO4 you multiply 0.5619 x 2/3 (since you're solving for NaPO, the 2 goes on top) which shows we have .3746 Moles of NaPO. Multiply times it's molar mass so 0.3746x 163.94g/mol= 61.4136 grams NaPO. I believe.
bonjours ma question est sin x=1/7 comment trouver les valeurs de x plz help my
Answer:
See figure 1
Explanation:
In the structure of nylon 6,6 we have <u>amide groups</u>. In this functional group, We have a nitrogen bond to hydrogen, so in this bond, we will have a <u>dipole</u>, due to the <u>electronegativity difference</u>. Nitrogen has more electronegativity than hydrogen, therefore a <u>positive dipole</u> would be generated in the hydrogen atom. Additionally, in the <u>carbonyl group</u> (C=O) due to the oxygen, we will have also a <u>dipole</u>, in this case, a <u>negative dipole</u> because the oxygen atom has <u>more electronegativity</u> (compare with carbon).
When we put two strings of nylon 6,6 the positive dipole will interact with the negative dipole and vice-versa and we will obtain the <u>"hydrogen bonds"</u>.
See figure 1
I hope it helps!