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olasank [31]
3 years ago
11

A water balloon is catapulted into the air so that it's height, in meters, after t seconds is h = -4.9t^ +27t +2.4

Mathematics
1 answer:
zysi [14]3 years ago
6 0
h = -4..9t^2+27t+2.4\ for\ t=3

Just replace t with 3 and solve.

h = -4.9*3^2 + 27*3 + 2.4 \\ h = -4.9*9 + 27*3 + 2.4 \\ h=-44.1 + 81 + 2.4 \\ \boxed{h=39.3}
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Solve this equation log3X + log3(x-6) = log3 7
ExtremeBDS [4]

Hello!

log₃(x) + log₃(x - 6) = log₃(7) <=>

<=> log₃(x * (x - 6)) = log₃(7) <=>

<=> log₃(x² - 6x) = log₃(7) <=>

<=> x² - 6x = 7 <=>

<=> x² - 6x - 7 = 0 <=>

<=> x² + x - 7x - 7 = 0 <=>

<=> x * (x + 1) - 7 * (x + 1) = 0 <=>

<=> (x + 1) * (x - 7) = 0 <=>

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<=> x = -1 and x = 7, x ∈ { 6; +∞ } <=>

<=> x = 7

Good luck! :)

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