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KATRIN_1 [288]
3 years ago
14

The elements least likely to form bonds are found in which group? O 15 O 16 017 O 18

Physics
2 answers:
12345 [234]3 years ago
7 0
The answer is group 18.

Explanation:
Group 18 is known as the Noble Gases. They are the most stable elements because they have a full outer shell of valence electrons, so they have no need to bond with other elements.
san4es73 [151]3 years ago
5 0

Answer:

D.

Explanation:

i just took the test and it right!

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Find the change in thermal energy of a 25kg severed clown doll head that heats up from 25°C to 35°C, and has the specific heat o
timama [110]

Answer:

Q = 425 kJ

Explanation:

Given that,

Mass, m = 25 kg

The clown doll head that heats up from 25°C to 35°C

The specific heat is 1700 J/kg°C

We need to find the internal energy of it. The heat required to raise the temperature is given by the formula as follows :

Q=mc\Delta T\\\\Q=25\times 1700\times (35-25)\\\\Q=425000\ J\\\\Q=425\ kJ

So, 425 kJ of thermal energy is severed.

6 0
3 years ago
A 40 kg bear slides, from rest, 14 m down a lodgepole pine tree, moving with a speed of 3.7 m/s just before hitting the ground.
antiseptic1488 [7]

Answer:

A. -5488J

B. 273.8J

C. 372.44N

Explanation:

Given:

m = 40kg

h = 14 m

v= 3.7 m/s

Part(a)

The change in the potential energy of the bear Earth system during the slide

AU = -mgh = -40(9.8) (14) = -5488 J

Part(b)

The kinetic energy of the bear just before hitting the ground is

Ks 1/2 mV^2= (40)(3.7)2 = 547.6 /2 = 273.8J

Part(c)

The change in the thermal energy of the system due to friction is

AEth = fxh=-(AK +AU) = 5488– 273.8 = 5214.2 J

The average frictional force that acts on the sliding bear is

F = Eth / 14= 5214.2/14 =372.44N

4 0
3 years ago
Read 2 more answers
Steam machines are used to sterilise kitchen work surfaces.
algol [13]

Answer:

Styleusso customer care number 8388026087//8388026087 refund ke liye call kare

5 0
3 years ago
What is the internal shell found in a squid
MakcuM [25]
The internal shell found in a squid is the pen.

3 0
4 years ago
A ball is thrown vertically upwards with a velocity v and an initial kinetic energy Ek. When half way to the top of its flight,
Mama L [17]

Answer:

Option A

\frac{V}{\sqrt{2} } ,\frac{E}{2}

Explanation:

When the ball its thrown up, at half way of its flight it means half of its vertical height which is \frac{h}{2}.  

potential energy = mgh

since it moved half way of height

P.E = \frac{mgh}{2}

This means for the body to have gained half of its P.E, it will loose half of its kinetic energy.

Final kinetic energy(E_{1}) = E/2

kinetic energy = \frac{1}{2}mv^{2}

let the final velocity at halfway flight be v1

E_{1} = E/2

\frac{1}{2}mv_{1}^{2} =\frac{\frac{1}{2}mv^{2}}{2}

cross multiply we have

mv_{1}^{2} =\frac{1}{2}mv^{2}

cancel m from both sides

v_{1}^{2} = \frac{1}{2}v^{2}

take the square root of both sides,

v_{1} =\sqrt{\frac{v^{2} }{2} }

v_{1} =\frac{v}{\sqrt{2} }

Thus our final velocities will be E/2 and \frac{v}{\sqrt{2} }

5 0
3 years ago
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