Answer:
2KI + Cl₂ → 2KCl + I₂
Explanation:
The reaction equation is given as:
KI + Cl₂ → KCl + I₂
The problem at hand is to balance this chemical reaction. To solve this problem we use a mathematical approach;
aKI + bCl₂ → cKCl + dI₂
Conserving K : a = c
I : a = 2d
Cl : 2b = c
Now let a = 1, c = 1 , d = 
, b = , ;
Multiply through by 2;
a = 2, b = 1 , c = 2, d = 1
2KI + Cl₂ → 2KCl + I₂
Answer:
option c is correct
Explanation:
we know that time rate of change of velocity is called acceleration
so a=v/t
a=12/4
a=3m/s²
-- If you're observing the moon from a location in the northern hemisphere, like Canada, Russia, the US, or Israel, then it looks like this picture during the <em>waxing crescent</em> phase.
-- If you're observing the moon from a location in the <u>southern</u> hemisphere, like Australia, South Africa, Paraguay, or Antarctica, then it looks like this picture during the <u>waning</u> crescent phase.
Answer:
(a) T = 0.412s
(b) f = 2.42Hz
(c) w = 15.25 rad/s
(d) k = 86.75N/m
(e) vmax = 5.03 m/s
Explanation:
Given information:
m: mass of the block = 0.373kg
A: amplitude of oscillation = 22cm = 0.22m
T: period of oscillation = 0.412s
(a) The period is the time of one complete oscillation = 0.412s
The period is 0.412s
(b) The frequency is calculated by using the following formula:
The frequency is 2.42 Hz
(c) The angular frequency is:
The angular frequency is 15.25 rad/s
(d) The spring constant is calculated by solving the following equation for k:
The spring constant is 86.75N/m
(e) The maximum speed is:
(f) The maximum force applied by the spring if for the maximum elongation, that is, the amplitude:
The maximum force that the spring exerts on the block is 17.35N
ANSWER:
F(h)= 230 N is the horizontal force you will need to move the pickup along the same road at the same speed.
STEP-BY-STEP EXPLANATION:
F(h) is Horizontal Force = 200 N
V is Speed = 2.4 m/s
The total weight increase by 42%
coefficient of rolling friction decrease by 19%
Since the velocity is constant so acceleration is zero; a=0
Now the horizontal force required to move the pickup is equal to the frictional force.
F(h) = F(f)
F(h) = mg* u
m is mass
g is gravitational acceleration = 9.8 m/s^2
200 = mg*u
Since weight increases by 42% and friction coefficient decreases by 19%
New weight = 1+0.42 = 1.42 = (1.42*m*g)
New friction coefficient = μ = 1 - 0.19 = 0.81 = 0.81 u
F(h) = (0.81μ) (1.42 m g)
= (0.81) (1.42) (μ m g)
= (0.81) (1.42) (200)
= 230 N
