Acceleration is any change in speed or direction of motion.
Speeding up, slowing down, or moving along a curve are all accelerations.
Answer:
m=0.5kg
h = 180 cm =1.8 mh=180cm=1.8m
Initial potential energy of the object is:
E_p=m*g*hE
p
=m∗g∗h
Kinetic energy at the surface:
E_k=\frac{mv^2}{2}E
k
=
2
mv
2
According to the law of conservation of energy (assuming no air resistance):
E_p = E_kE
p
=E
k
mgh=\frac{mv^2}{2}mgh=
2
mv
2
Solving for v:
v=\sqrt{2gh}v=
2gh
p=mvp=mv
So,
p= m*v = m\sqrt{2gh}p=m∗v=m
2gh
Calculating:
p= 0.5\sqrt{2*9.8*1.8}\approx 2.97 \frac{kg*m}{s}p=0.5
2∗9.8∗1.8
≈2.97
s
kg∗m
Answer:
p \approx 2.97 \frac{kg*m}{s}p≈2.97
s
kg∗m
A. because as the merry-go-round spins the child accelerates towards the center of the merry-go-round at a uniform rate.
Answer:
40 j, 80j.
Explanation:
P.E= mgh. G=10 m/s².
For 4m, P.E=1*10*4=40 joules.
For 8m, P.E=1*10*8=80 joules.
Answer:
137.8 N
Explanation:
First we need to find the acceleration of the sprinter. To do so, we can use the Torricelli's equation:
V^2 = Vo^2 + 2*a*S
9^2 = 2^2 + 2*a*25
81 = 4 + 50a
50a = 77
a = 77/50 = 1.54 m/s2
Now, to find the resulting force in the sprinter, we can use the following equation:
Force = mass * acceleration
Force = 70 * 1.54 = 107.8 N
If we have a 30 N force against the sprinter, the total force applied is:
Resulting force = Applied force - Wind force
107.8 = Applied force - 30
Applied force = 137.8 N