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2 years ago

Which process moves molecules and has these traits?

Physics

2 answers:

miv72 [106K]2 years ago

8 0

Answer:

que onda me siento superior solo por hablar español ✌️

nekit [7.7K]2 years ago

4 0

Diffusion is the right answer, because technically the only acceptable answers here are diffusion and osmosis. But osmosis occurs in a semi-membrane, leaving no choice but diffusion. (My bad if my answer is incorrect)

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Does mars has a bulge near its equator ?

Keith_Richards [23]

Yessir it sure does

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3 years ago

What is one way the biosphere can affect the geosphere

erica [24]

Answer: B

Explanation:

Biosphere breaks down rock of the geosphere (plant roots), but when it comes to soil, minerals of the geosphere feed the plants. Biosphere and atmosphere interact through animal and plant respiration of oxygen and carbon dioxide. Geosphere creates, destroys and keeps various biosphere places safe.

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3 years ago

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Adaptive radiation is demonstrated by ____

Vlad1618 [11]

X-rays are high energy electrons that can cause damage when exposed under extreme conditions. The best technology that can block it is using a lightweight type of metal foam. It can take in high energy collisions which also exhibits high forces. it does not only block x-rays but also, neutron radiation and gamma rays.

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3 years ago

An electron enters a region with a speed of 5×10^6m/s and is slowed down at the rate of 1.25×10^-4m/s². How far does the electro

Mashutka [201]

1) The distance travelled by the electron is $1\cdot 10^{17} m$

2) The time taken is $4.0\cdot 10^{10}s$

Explanation:

The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance travelled

For the electron in this problem,

$u=5\cdot 10^6 m/s$ is the initial velocity

v = 0 is the final velocity (it comes to a stop)

$a=-1.25\cdot 10^{-4} m/s^2$ is the acceleration

Solving for s, we find the distance travelled:

$s=\frac{v^2-u^2}{2a}=\frac{0-(5\cdot 10^6)^2}{2(-1.25\cdot 10^{-4})}=1\cdot 10^{17} m$

The total time taken for the electron in its motion can also be found by using another suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

Here we have

$u=5\cdot 10^6 m/s$

v = 0

$a=-1.25\cdot 10^{-4} m/s^2$

And solving for t, we find the time taken:

$t=\frac{v-u}{a}=\frac{0-5\cdot 10^6}{-1.25\cdot 10^{-4}}=4.0\cdot 10^{10}s$

Learn more about accelerated motion:

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#LearnwithBrainly

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3 years ago

A bob attached to a string of length L = 1.25 m, initially found at the equilibrium

malfutka [58]

The maximum displacement angle of the bob is 13⁰.

The given parameters;

<em>Length of the pendulum, L = 1.25 m</em>
<em>Initial velocity of the bob, v = 0.8 m/s</em>

The maximum displacement of the bob is calculated by applying the principle of conservation of energy;

$P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{0.8^2}{2\times 10} \\\\h = 0.032 \ m$

The maximum displacement angle is calculated as follows;

$cos \theta = \frac{L-h}{L} \\\\cos \theta = \frac{1.25 - 0.032}{1.25} \\\\\cos \theta = \frac{1.218}{1.25} \\\\cos \theta = 0.9744\\\\\theta = cos^{-1}(0.9744)\\\\\theta = 13\ ^0$

Thus, the maximum displacement angle of the bob is 13⁰.

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3 years ago