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murzikaleks [220]
2 years ago
13

A 2,000-kg test car, traveling 60 m/s hits a brick wall. Using motion pictures, the time involved is determined to be 0.050 s. W

hat is the change in momentum of the car?
A) +1.2 x 10^5

B)-1.2 x 10^5
Physics
1 answer:
Naily [24]2 years ago
8 0

change in momentum of car is given as

\Delta P = P_f - P_i

here we have

\Delta P = m(v_f - v_i)

given that

m = 2000 kg

v_f = 0

v_i = 60 m/s

now we have

\Delta P = 2000(0 - 60)

\Delta P = - 1.2 \times 10^5 kg m/s

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Inga [223]

Answer:

heat pressure, electron degeneracy, neutron degeneracy, and nothing

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White dwarf: It is the end stage of a medium sized star like the Sun. Outer layers of the star are thrown in the form a shell/bubble leaving a small and dense core in the center called as white dwarf. This core consists of carbon and oxygen. Nuclear fusion doesn't occur in the core of white dwarfs. The inward gravity is balanced by the electron degeneracy pressure. Thus these stars will keep on radiating the remaining heat and will turn in to a black dwarf at the end.

Neutron Star: This is the end stage of a supermassive star (1-3 times the mass of the Sun). At the last stage of the life the core collapses. In these stars the inward gravity is so huge that the pressure overcomes the electron degeneracy pressure and crushes together the electron and proton to form neutron. The neutron then stops the collapse and balances the inward gravity.

Black Hole: This is the end stage of a hyper massive stars weighing more than 3 times the mass of the Sun. The inward gravitational force is so huge that even the neutrons are not able to stop the collapse the core. thus the mass of the star collapses into a very small area of immense gravity. There is nothing that can balance this inward gravity.

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or time=t=14s

putting values in eq(1)

a=33.3/14

a=2.378 m/s^2

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3 years ago
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