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4 years ago

The symbols used on a map are explained in the

1 answer:

5 0

Answer - LEGEND

The legend of a map is also called the map key. It is the part included in a map to, as it were, unlock the map. The legend (or map key) gives explanation to what each symbol and color used in the map represents.

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When 10.0 grams of CH4 reacts completely with 40.0 grams of O2 such that there are no reactants left over, 27.5 grams of carbon

BARSIC [14]

Answer:

$\boxed{\text{27.4 g CO$_{2}$; 22.5 g H$_{2}$O}}}$

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 16.04 32.00 44.01 18.02

CH₄ + 2O₂ → CO₂ + 2H₂O

m/g: 10.0 40.0

1. Moles of CH₄

$\text{Moles of CH}_{4} = \text{10.0 g CH}_{4} \times \dfrac{\text{1 mol CH}_{4}}{\text{16.04 g CH}_{4}} = \text{0.6234 mol CH}_{4}$

2. Mass of CO₂

(i) Calculate the moles of CO₂

The molar ratio is (1 mol CO₂ /1 mol CH₄)

$\text{Moles of CO$_{2}$} = \text{0.6234 mol CH$_4$} \times \dfrac{\text{1 mol CO$_{2}$}} {\text{1 mol CH$_{4}$}} = \text{0.6234 mol CO$_{2}$}$

(ii) Calculate the mass of CO₂

$\text{Mass of CO$_{2}$} = \text{0.6234 mol CO$_{2}$} \times \dfrac{\text{44.01 g CO$_{2}$}}{\text{1 mol CO$_{2}$}} = \textbf{27.4 g CO$_{2}$}\\\\\text{The mass of carbon dioxide formed is } \boxed{\textbf{27.4 g CO$_{2}$}}$

3. Mass of H₂O

(i) Calculate the moles of H₂O

The molar ratio is (2 mol H₂O /1 mol CH₄)

$\text{Moles of H$_{2}$O}= \text{0.6234 mol CH}_{4} \times \dfrac{\text{2 mol H$_{2}$O}}{\text{1 mol CH$_{4}$}} = \text{1.247 mol H$_{2}$O}$

(ii) Calculate the mass of H₂O

$\text{Mass of H$_{2}$O} = \text{1.247 mol H$_{2}$O } \times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}} = \textbf{22.5 g H$_{2}$O}\\\\\text{The mass of water formed is } \boxed{\textbf{22.5 g H$_{2}$O}}$

4 0

3 years ago

I WILL GIVE BRAINLIEST

juin [17]

Answer:

Volumes can have the same volume but different masses if they have different densities. For example, a 10 x 10 x 10 block of lead has the same volume as a 10 x 10 x 10 block of pine wood, but the lead block weighs 22.6 times more than the pine block. Indeed, the density of lead is high enough that the lead block will sink in water, whereas the pine block's density is low enough that the pine block will float in water.

Volume is a measurement, the units are cubic metres or cubic centimetres. Litres = 1000 cm3

Mass is a measurement, the units are grams, kilograms.

^^^^^^^^^^^^^^^^^^

to that answer.

Mass is not weight. it is the amount of matter an object takes up. Therefore, saying that a lead block weights 22.6 times more than the pine block does not answer how an object can have different masses but the same volume. :D

5 0

3 years ago

the roof of a building is 0.2km^2. during a rainstorm, 5.5 cm of rain was measured to be sitting on the roof. what is the mass i

Nikolay [14]

The mass in kg of the water on the roof after the rainstorm is mathematically given as

The mass of the water on the roof after a rainstorm is 1.1 *10^{10}g or 1.1*10^{7}kg

<h3>What is the mass in kg of the water on the roof after the rainstorm? </h3>

Generally, the equation for the Area of the roof is mathematically given as

$A=0.20 \times 10^{10} \mathrm{~cm}^{2}$

height of the rain =5.5cm

the volume of the rain on the roof =1.1 * 10^{10} CC

Generally, the equation for mass is mathematically given as

mass=volume*density

$&=\left(1.1 \times 10^{10} \mathrm{cC} \times 1 \mathrm{~g} / \mathrm{cc}\right) \\&=1.1 \times 10^{10} \mathrm{~g}$

In conclusion, the Mass of the water on the roof after a rainstorm is 1.1 *10^{10} or $1.1*10^{7}

Read more about Mass

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7 0

2 years ago

Sodium carbonate (na2co3) is used to neutralize the sulfuric acid spill. how many kilograms of sodium carbonate must be added to

jenyasd209 [6]

<span>5.45 x 10^3 kg of sodium carbonate is needed to neutralize 5.04 kg of sulfuric acid. For this, I will assume you have pure H2SO4. So first, you need to calculate the molar mass of H2SO4 and Na2CO3. Lookup the atomic weights of all the elements involved. Atomic weight of Sodium = 22.989769 Atomic weight of Sulfur = 32.065 Atomic weight of Carbon = 12.0107 Atomic weight of Oxygen = 15.999 Atomic weight of Hydrogen = 1.00794 Molar mass of H2SO4 = 2 * 1.00794 + 32.065 + 4 * 15.999 = 98.07688 g/mol Molar mass of Na2CO3 = 2 * 22.989769 + 12.0107 + 3 * 15.999 = 105.987238 g/mol The balanced equation for the reaction of Na2CO3 with H2SO4 is Na2CO3 + H2SO4 => Na2SO4 + CO2 + H2O so for every mole of sulfuric acid to be neutralized, you need 1 mole of sodium carbonate. You can determine the number of moles of sulfuric acid you have and then calculate the mass of that many moles of sodium carbonate. But, there's an easier way. Just use the relative mass differences between sodium carbonate and sulfuric acid. So 105.987238 g/mol / 98.07688 g/mol = 1.080655 So that means for every kg of sulfuric acid, you need 1.080655 kg of sodium carbonate. Now do the multiplication. 5.04 x 10^3 kg * 1.080655 = 5.4465 x 10^3 kg. Since you only have 3 significant figures for your data, round the result to 3 significant figures, giving 5.45 x 10^3 kg</span>

3 0

3 years ago

Zachary is tasked with carefully measuring precisely one mole of aluminum. How should Zachary go about completing this assignmen

Advocard [28]

27g of Aluminium

Explanation:

For Zachary tasked with obtaining one mole of aluminium, weighing 27g of the compound gives 1 mole of the element.

A mole is a simple unit of quantifying particles of a substance.

It is the amount of substance that contains the avogadro's number of particles.

The molar mass of a substance is the mass in gram of one mole of a substance.

The molar mass of Aluminium is 27g/mol

This is implies 1 mole aluminium has a mass of 27g.

Mass = number of moles x molar mass = 1 mole x 27g/mole = 27g

learn more:

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6 0

3 years ago