Answer:0.477 g/ml
Explanation:
Density=(40.14-33.79)/13.3 ml
Density=6.35/13.3
Density=0.477 g/ml
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Answer:
49.4 mol Oxygen
Explanation:
Mg(NO3)2 ----- 6 O
1 mol 6 mol
8.24 mol x mol
x = 8.24*6/1 = 49.44 mol ≈ 49.4 mol Oxygen
Answer : The temperature of neon gas will be, 221.0 K
Explanation :
To calculate the temperature of neon gas we are using ideal gas equation.
where,
P = pressure of neon gas = 96.7 kPa = 0.955 atm
Conversion used : (1 atm = 101.3 kPa)
V = volume of neon gas = 9.50 L
T = temperature of neon gas = ?
R = gas constant = 0.0821 L.atm/mole.K
w = mass of neon gas = 10.00 g
M = molar mass of neon gas = 20 g/mole
Now put all the given values in the ideal gas equation, we get:
Therefore, the temperature of neon gas will be, 221.0 K