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ryzh [129]
3 years ago
8

1.open intervals on which the function is increasing

Mathematics
1 answer:
Eddi Din [679]3 years ago
6 0

i think the answer is c

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Given the following triangle, if b = 9 and B = 15°, find a.<br><br> 0.27<br> 2.41<br> 33.59
SVEN [57.7K]
SOH,CAH, TOA so it would be TANGENT since it would be Opposite over Adjacent. Tan(15) = 9/a put Tan(15) onto your calculator it would be .267949 round that to .27 = 9/a cross multiply  
a = 33.588. C is the correct answer.
7 0
3 years ago
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Find x, the unknown side.<br><br> A) 4.6<br> C) 4.8<br> B) 5.4<br> D)3.5
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Go ahead to do the trick
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2 years ago
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Unit activity: exponential and logarithmic functions
nirvana33 [79]

We will conclude that:

  • The domain of the exponential function is equal to the range of the logarithmic function.
  • The domain of the logarithmic function is equal to the range of the exponential function.

<h3>Comparing the domains and ranges.</h3>

Let's study the two functions.

The exponential function is given by:

f(x) = A*e^x

You can input any value of x in that function, so the domain is the set of all real numbers. And the value of x can't change the sign of the function, so, for example, if A is positive, the range will be:

y > 0.

For the logarithmic function we have:

g(x) = A*ln(x).

As you may know, only positive values can be used as arguments for the logarithmic function, while we know that:

\lim_{x \to \infty} ln(x) = \infty \\\\ \lim_{x \to0} ln(x) = -\infty

So the range of the logarithmic function is the set of all real numbers.

<h3>So what we can conclude?</h3>
  • The domain of the exponential function is equal to the range of the logarithmic function.
  • The domain of the logarithmic function is equal to the range of the exponential function.

If you want to learn more about domains and ranges, you can read:

brainly.com/question/10197594

3 0
2 years ago
X+6-5=8-2 <br> x=? <br> solve the following equation. then place the correct number in the box
Valentin [98]
X
+
6
−
5
=
8
−
2

+
6
−
5
=
8
−
2
Solve
1
Subtract the numbers
x
+
6
−
5
=
8
−
2

+
6
−
5
=
8
−
2
x
+
1
=
8
−
2

+
1
=
8
−
2
2
Subtract the numbers
x
+
1
=
8
−
2

+
1
=
8
−
2
x
+
1
=
6

+
1
=
6
3
Subtract
1
1
from both sides
x
+
1
=
6

+
1
=
6
x
+
1
−
1
=
6
−
1

+
1
−
1
=
6
−
1
4
Simplify
Subtract the numbers
Subtract the numbers
x
=
5

=
5
7 0
2 years ago
1. A hotel is in the shape of a​ cylinder, with a circular foundation. The circumference of the foundation is 2 times the​ radiu
AysviL [449]

2)The circumference or perimeter of a circle with radius r is

P=2\pi r. Given P=28\pi. Therefore,

2\pi r =28\pi \\ r=14\\ d=2r=28\\ A=\pi r^2 \\ A=\pi (14)^2\\ A=[tex] 196\pi

Thus the radius is 14\;ft, diameter 28\;ft and area 196\pi \;ft^2

7 0
3 years ago
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