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Elza [17]
4 years ago
14

Points A and B lie above an infinite plane of negative charge that produces a uniform electric field of strength E=10 N/C. What

is the potential difference ΔV = VB - VA between points A and B if the points are separated by a distance of 3m as illustrated below?
Physics
1 answer:
olasank [31]4 years ago
4 0

There is no illustration of the problem provided but I'll attempt to provide an answer.

The relationship between the electric potential difference between two points and the average strength of the electric field between those two points is given by:

║E║ = ΔV/d

║E║ is the magnitude of the average electric field, ΔV is the potential difference between A and B, and d is the distance between A and B.

We are given the following values:

║E║= 10N/C

d = 3m

Plug these values in and solve for ΔV

10 = ΔV/3

ΔV = 30V

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