Answer:
The mass flow rate is 2.37*10^-4kg/s
The exit velocity is 34.3m/s
The total flow of energy is 0.583 KJ/KgThe rate at which energy leave the cooker is 0.638KW
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Explanation:
Equilibrium position in y direction:
W = Fb (Weight of the block is equal to buoyant force)
m*g = V*p*g
V under water = A*h
hence,
m = A*h*p
Using Newton 2nd Law

Hence, T time period
T = 2*pi*sqrt ( h / g )
When light travels from a medium with higher refractive index to a medium with lower refractive index, there is a critical angle after which all the light is reflected (so, there is no refraction).
The value of this critical angle can be derived by Snell's law, and it is equal to

where n2 is the refractive index of the second medium and n1 is the refractive index of the first medium.
In our problem, n1=1.47 and n2=1.33, so the critical angle is
Answer:
The work done by the applied force is 259.22 J.
Explanation:
The work done by the applied force is given by:

Where:
F: is the applied horizontal force = 108.915 N
d: is the distance = 2.38 m
Hence, the work is:

Therefore, the work done by the applied force is 259.22 J.
I hope it helps you!