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ch4aika [34]
3 years ago
8

Which state of matter has the greatest distance between the individual particles

Physics
2 answers:
Savatey [412]3 years ago
7 0
The gaseous state has the greatest distance between the individual particles.
anyanavicka [17]3 years ago
5 0

Answer:

C

Explanation:

It was correct on USA test prep.

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A cruise ship made a trip to Guam and back. The trip there took 12 hours and the trip
Alecsey [184]

Answer:

The average speed is 8.0 km/h

Explanation:

We use the data for the return journey to calculate the distance travelled using the constant velocity equation:

s  =  v  t  =6*4=24km

 

Note I didn't change any units so the answer comes out in kilometres.

Now use the distance and time taken to travel to Guam to find the average speed:

v=st=24/3=8.0km/h

6 0
3 years ago
For which pair of launch angles will two identical projectiles have equal ranges?. A. 19.24°, 80.54°B. 16.42°, 74.58°C. 60.23°,
AlladinOne [14]
The kinematic equations of motion that apply here are<span>y(t)=votsin(θ)−12gt2</span>and<span>x(t)=votcos(θ)</span>Setting y(t)=0 yields <span>0=votsin(θ)−12gt2</span>. If we solve for t, we obtain, by factoring,<span>t=<span>2vsin(θ)g</span></span>Substitute this into our equation for x(t). This yields<span>x(t)=<span><span>2v2cos(θ)sin(θ)</span>g</span></span><span>This is equal to x=<span><span>v^2sin(2θ)</span>g</span></span>Hence the angles that have identical projectiles are have the same range via substitution in the last equation is C. <span> 60.23°, 29.77° </span>
4 0
3 years ago
Read 2 more answers
Find the magnitude: || 5-3i || ...?
____ [38]
The magnitude would be :

\sqrt{5^2 + 3^2}

= √34

Hope this helps
5 0
3 years ago
An ice skater is spinning at 6.00 rev/s with his moment of inertia being 0.400 kg/m2. Calculate his new moment of inertia if he
labwork [276]

Answer:

New moment of inertia will be I=1.92kgm^2

Explanation:

It is given initially angular velocity \omega =6rev/sec=6\times 2\pi =37.68rad/sec

Moment of inertia I=0.4kgm^2

Angular momentum is equal to L=I\omega =37.68\times 0.4=15.072kgm^2/sec

Now angular velocity is decreases to \omega =1.25rev/sec=1.25\times 2\times 3.14=7.85rad/sec

As we know that angular momentum is conserved

So 15.072=I\times 7.85

I=1.92kgm^2

So new moment of inertia will be I=1.92kgm^2

4 0
3 years ago
the roque requried to turn the crank on an ice cream maker is 4.50 N.m how much work does it take to turn the crank through 300
Alexus [3.1K]

Answer:

the work required to turn the crank at the given revolutions is 8,483.4 J

Explanation:

Given;

torque required to turn the crank, T = 4.50 N.m

number of revolutions, = 300 turns

The work required to turn the crank is given as;

W = 2πT

W = 2 x 3.142 x 4.5

W = 28.278 J

1 revolution = 28.278 J

300 revlotions = ?

= 300 x 28.278 J

= 8,483.4 J

Therefore, the work required to turn the crank at the given revolutions is 8,483.4 J

4 0
3 years ago
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