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3 years ago

Jenny puts a book on her desk. she lifts the book up with her finger, using a force of 0.5N .The cover is 10cm wide .

Physics

1 answer:

zepelin [54]3 years ago

6 0

The turning moment on the cover of the book is 0.05 Nm.

Explanation:

Given:

Force applied (F) = 0.5 N

Distance covered (d) = 10 cm

Converting Distance covered from cm to meter we get (d)= 0.1 m

To find:

Turning Moment (M) on the cover of the book = ?

Formula to be used:

Turning Moment (M) = F × d

= 0.5 × 0.1

= 0.05 Nm

Thus the turning moment on the cover of the book is found to be 0.05 Nm

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Answer:

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Explanation:

The relative velocity of the satellites, v = 0.190 m/s

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$v_2 = \dfrac{2 \cdot m_1}{m_1 + m_2} \cdot u_1 - \dfrac{m_1 - m_2}{m_1 + m_2} \cdot u_2$

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v₁ and v₂ = The final velocities of the satellites

We get;

$v_1 = \dfrac{2 \times 4.0 \times 10^3}{4.0 \times 10^3 + 7.50 \times 10^3} \times 0.095 - \dfrac{4.0 \times 10^3- 7.50\times 10^3}{4.0 \times 10^3+ 7.50\times 10^3} \times 0.095 = 0.095$

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The final relative velocity of the satellite, $v_f$ = v₁ + v₂

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