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2 years ago

Could anyone help me out ?

Physics

2 answers:

Delicious77 [7]2 years ago

4 0

density = mass/volume = 100kg/10ml = 10kg/ml

voluime = mass/density = 50g/2 g/ml = 25 ml

mass = density x volume = 2x55 = 110 kg

CaHeK987 [17]2 years ago

4 0

All of these are answered by using one formula . . . the definition of Density. Density = Mass / Volume . For each problem, substitute the given numbers into that formula, and solve it for the unknown number. (Don't forget to keep the correct units all the way through each one.)

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In your opinion, is "avoiding" an effective conflict management strategy? Why or why not?

soldi70 [24.7K]

In my personal opinion, avoiding in not an effective conflict management strategy. When you are avoiding a conflict, you are really just pushing it to the side and it will need to be dealt with sooner or later. Avoiding a conflict is also ammeter thing to do as well, you should take responsibility and handle any situation.

4 0

3 years ago

Read 2 more answers

A train is traveling at a speed of 80\,\dfrac{\text{km}}{\text{h}}80 h km 80, start fraction, start text, k, m, end text, divi

trasher [3.6K]

Answer:

The distance the train travels before coming to a (complete) stop = 40/81 km which is approximately 493.83 meters

Explanation:

The initial speed of the train u = 80 km/h = 22 2/9 m/s = 22. $\bar 2$ m/s

The magnitude of the constant acceleration with which the train slows, a = 0.5 m/s²

Therefore, we have the following suitable kinematic equation of motion;

v² = u² - 2 × a × s

Where;

v = The final velocity = 0 (The train comes to a stop)

s = The distance the train travels before coming to a stop

Substituting the values gives;

0² = 22. $\bar 2$ ² - 2 × 0.5 × s

2 × 0.5 × s = 22. $\bar 2$ ²

s = 22. $\bar 2$ ²/1 = 493 67/81 m = 40/81 km

The distance the train travels before coming to a (complete) stop = 40/81 km ≈ 493.83 m.

7 0

2 years ago

Read 2 more answers

How do I do these? My teacher didn’t show us how.

melisa1 [442]

Explanation:

Displacement is simply the change in position. So in the first part of problem 1, looking at the graph between 0 s and 2 s, the position changes from 0 m to -4 m. So the displacement is:

Δx = -4 m − 0 m

Δx = -4 m

Between 2 s and 4 s, the position stays at -4 m. The displacement is:

Δx = -4 m − (-4 m)

Δx = 0 m

Finally, between 4 s and 6 s, the position goes from -4 m to 6 m. The displacement is:

Δx = 6 m − (-4 m)

Δx = 10 m

The net displacement is the change in position from 0 s to 6 s:

Δx = 6 m − 0 m

Δx = 6 m

In the second part of problem 1, we have a velocity vs time graph.

Car 1 starts with 0 velocity and ends with a velocity of 6 m/s, so it is accelerating and constantly moving to the right.

Car 2 starts with a velocity of -6 m/s and ends with a velocity of 6 m/s. It is also accelerating, but first it is moving to the left, comes to a stop at t = 3 s, then moves to the right.

Car 3 starts with a velocity of 2 m/s and ends with a velocity of 2 m/s. So it is moving constantly to the right, but never speeds up or slows down.

We want to know when two of the cars meet. Unfortunately, this isn't as easy as looking for where the lines cross on the graph. We need to calculate their displacements. We can do this by finding the area under the graph (assuming all the cars start from the same point).

Let's start with Car 2. Half of the area is below the x-axis, and half is above. Without doing calculations, we can say the total displacement for this car is 0. This means it ends back up where it started, and that it never meets either of the other cars, both of which have positive displacements.

So we know Car 1 and Car 3 meet, we just have to find where and when. For Car 1, the area under the curve is a triangle. So its displacement is:

Δx = ½ t v(t)

where t is the time and v(t) is the velocity of Car 1 at that time. Since the line has a slope of 1 and y intercept of 0, we know v(t) = t. So:

Δx = ½ t²

Now look at Car 3. The area under the curve is a rectangle. So its displacement is:

Δx = 2t

When the two cars have the same displacement:

½ t² = 2t

t² = 4t

t² − 4t = 0

t (t − 4) = 0

t = 0, 4

t = 0 refers to the time when both cars are at the starting point, so t = 4 is the answer we're looking for. Where are the cars at this time? Simply plug in t = 4 into either of the equations we found:

Δx = 8

So Cars 1 and 3 meet at 4 s and 8 m.

7 0

2 years ago

All electric devices are required to have identifying plates that specify their electrical characteristics. The plate on a certa

masha68 [24]

Answer:

R= 20 ohm

Explanation:

Given that

Current ,I = 6 A

Voltage difference ,ΔV = 120 V