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Natalija [7]
3 years ago
9

Please help me!

Physics
2 answers:
mihalych1998 [28]3 years ago
7 0
The answer would be mass movement 
Kay [80]3 years ago
5 0
Runoff because the mud is a liquid and moves on an amount of water that is in it like with quicksand
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ZanzabumX [31]

The answer is A.

A positive charge’s electric field pushes out.

Hope this helps! -Avenging

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3 years ago
I need some help with this,, anyone??<br>It's has three parts so... (9A), (9B), and (9C)
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A is 588N.

b) When she reaches her terminal speed, 10 seconds into the dive, she is no longer accelerating, so the net force on her is zero.
Think of it this way: If the net force were not zero she would continue to accelerate.

c) She is no longer accelerating.
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3 years ago
HELP!!!!
BigorU [14]
Time = 13.5 / 2.5 = 5.4 seconds
4 0
3 years ago
Read 2 more answers
A team of astronauts is on a mission to land on and explore a large asteroid. In addition to collecting samples and performing e
sergij07 [2.7K]

Answer:

9.60 m/s

Explanation:

The escape speed of an object from the surface of a planet/asteroid is given by:

v=\sqrt{\frac{2GM}{R}}

where

G is the gravitational constant

M is the mass of the planet/asteroid

R is the radius of the planet/asteroid

In this problem we have

\rho = 2.02\cdot 10^6 g/m^3 is the density of the asteroid

V=3.09\cdot 10^{12}m^3 is the volume

So the mass of the asteroid is

M=\rho V=(2.02\cdot 10^6 g/m^3)(3.09\cdot 10^{12} m^3)=6.24\cdot 10^{18} g=6.24\cdot 10^{15} kg

The asteroid is approximately spherical, so its volume can be written as

V=\frac{4}{3}\pi R^3

where R is the radius. Solving for R,

R=\sqrt[3]{\frac{3V}{4\pi}}=\sqrt[3]{\frac{3(3.09\cdot 10^{12} m^3)}{4\pi}}=9036 m

Substituting M and R inside the formula of the escape speed, we find:

v=\sqrt{\frac{2(6.67\cdot 10^{-11})(6.24\cdot 10^{15})}{(9036)}}=9.60 m/s

7 0
4 years ago
Which of the following quantities is measured by the area under the velocity time graph? (a) Magnitude of velocity (b) Magnitude
bearhunter [10]

Answer:

c.

magnitude of displacement

5 0
3 years ago
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