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3 years ago

Please help me!

Physics

2 answers:

mihalych1998 [28]3 years ago

7 0

The answer would be mass movement

Kay [80]3 years ago

5 0

Runoff because the mud is a liquid and moves on an amount of water that is in it like with quicksand

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A raging bull of mass 700kg runs at 10 m/s. How much kinetic energy does it have?

Illusion [34]

Answer: 35000 J or 35kJ

Explanation:

Use equation for kinetic energy : Ek=mV²/2

m=700 kg

V=10m/s

-------------------

Ek= 700kg*100m²7s²/2

Ek=35000 J=35kJ

6 0

3 years ago

If your car tachometer says your engine is moving at 1200 RPM, then what is it's angular velocity in Rad/sec?

Ostrovityanka [42]

Answer:

125.66 R/s

Explanation:

First 1200 r / min = 20 r/sec

20 r/s * 2pi Radians / r = 40 pi Radians / sec = 125.66 R/s

3 0

2 years ago

What is measurement ?...

mariarad [96]

Answer:

the size, length, or amount of something, as established by measuring.

3 0

2 years ago

Read 2 more answers

A bob of mass m = 0.250 kg is suspended from a fixed point with a massless string of length L = 22.0 cm. You will investigate th

katen-ka-za [31]

To solve the problem, it is necessary to use the concepts of gravitational force, centripetal force and trigonometric components that can be extrapolated from the statement.

By definition we know that the Force of Gravity is given by

$F_g=mg$

Where,

m= Mass

g = Gravitational Acceleration

The centripetal force is given by,

$F_c = \frac{mv^2}{R}$

Where,

m = Mass

v = Velocity

R = Radius

For the case described in the problem, the Force of gravity the net component would be given by sin?, While for the centripetal force the net component is in the horizontal direction, therefore it corresponds to the $cos\theta$

Then,

$F_g = mg sin\theta$

$F_c = \frac{mv^2}{r}cos\theta$

From the radius we have its length but not the net height, which would be given by

$r = L sin\theta$

So equating the equations we have to

$F_g = F_c$

$mg sin\theta=\frac{mv^2}{r}cos\theta$

$mg sin\theta=\frac{mv^2}{Lsin\theta}cos\theta$

Re-arrange to find v,

$v = \sqrt{\frac{gLsin^2\theta}{cos\theta}}$

Replacing with our values

$v = \sqrt{\frac{(9.8)(22*10^{-2})(sin^2 24)}{cos24}}$

$v = 0.624$

Therefore the tangential velocity of the mass is 0.624m/s

5 0

4 years ago

Organ pipe a, with both ends open, has a fundamental frequency of 340 hz. the third harmonic of organ pipe b, with one end open,

Sphinxa [80]

The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V= 343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is
F3₀ = 3V/4LC
The second harmonic of open pipe 'A' is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is
Lc = 37.83cm

7 0

3 years ago