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3 years ago

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If a firm holds a pure monopoly in the market and is able to sell 5 units of output at $4.00 per unit and 6 units of output at $

3,90 per unit, it will produce and sell the sixth unit if its marginal cost is
$3.40 or less

1 answer:

SIZIF [17.4K]3 years ago

8 0

Explanation:

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Scrappers Supplies tracks the number of units purchased and sold throughout each accounting period but applies its inventory cos

elena-s [515]

Answer:Inventory on hand Balance at the end = $4620

Explanation:

The question is unclear with regards to the requirements. however having dealt with questions of this nature in the past, I will assume the question requires us to calculate the cost of inventory on hand.

Opening Inventory balance = 180 x $28 =$5040

Purchased inventory = 290 x $30 = $8700

Cash sale (330 x $44) = $14520

Purchase inventory (230 x 34 ) = $7820

Cash sale (55 x $44) = $2420

Inventory on hand Balance = 5040+ 8700 - 14520 + 7820 - 2420

Inventory on hand Balance at the end = 4620 = $4620

8 0

3 years ago

An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi

Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

$\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}$

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

$1000000\sqrt{9+x^{2}$

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)$

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000$

<h2>f'(x)=0</h2>

$f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}} = 500000\\\frac{2x}{\sqrt{9+x^2}} = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\$

And we plug square root of 3 in the original cost function ad we get

$f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\$

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0

3 years ago

Stronx Consulting tests its salespeople on listening skills and then implements a training program to teach all of them to be be

nadya68 [22]

Answer:

The actual impact of the training can only be evaluated by comparing the performance of employees who underwent training and those who did not.

Explanation:

The reason is that when you conduct a post-lecture listening test then you are actually testing how much the person has absorbed the lecture which will not be reflected in the work that he will be assigned in near future. The main purpose of the training session is to make the workforce able to actually reflect the training lecture in the future work. This means if I want to increase the efficiency of the workforce then I will prefer to see whether or not the workforce which was trained have increased its work efficiency than the person who were not trained.

7 0

3 years ago

Beatrice Markets is expecting a period of intense growth and has decided to retain more of its earnings to help finance that gro

VLD [36.1K]

Answer: $16.69

Explanation:

Using the Dividend growth model, the value is:

= [Dividend 1/ (1 + required return)] + [Dividend 2/ (1 + required return)²] + [Terminal value / (1 + required return)²]

Terminal value = Dividend after 2 years / (required return - growth)

= 2.50/ (14.5% + 0%)

= $17.24

Dividend 1 = 3.60 * ( 1 -30%) Dividend 2 = 2.52 * ( 1 -30%)

= $2.52 = $1.76

Market value = (2.52 / 1.145) + (1.76 / 1.145²) + (17.24/1.145²)

= $16.69

3 0

3 years ago

Tamarisk, Inc. has 12000 shares of 5%, $100 par value, non-cumulative preferred stock and 48000 shares of $1 par value common st

hjlf

Answer:

$84,000

Explanation:

preference share dividend is at 5% on $100 par value. The number of preference shares is 12,000 shares ( non cumulative)

The year 2017 preference share dividend pay out is 5% of 100 multiplied by 12,000 = $60,000

Deduct $ 60,000 from $144,000 dividend declared in 2017 , the balance is common stockholders dividend.

144,000 minus 60,000 = $84,000

Non cumulative preference shares dividend are paid first for the year the company declares dividend. The dividend is not cumulative ( prior years dividend for which company did not declare dividend are forfeited).

The common stockholders are paid dividend after preference shares dividend are paid. The common stockholders bears the full risk of the business as seen above. In event of liquidation, they are the last to be settled from realised asset of the bankrupt company.

7 0

3 years ago