A. Usually friction slows things down. Can you imagine a scenario where it speeds things up? Describe

Physics

1 answer:

son4ous [18]3 years ago

3 0

Answer:

For example, when a person walk

Explanation:

The force of friction is a resistive force that opposes the motion of objects. It is produced by the contact between two surfaces: since the surfaces are not perfectly smooth, there are "microbumps" that cause a resistive force in the relative motion of the two surface.

This force is evident, for example, when we try to push a crate along the floor: as we push forward, there is a resistive force acting in the opposite direction, and this force is the force of friction.

The force of friction is in the direction opposite to the motion of the object, so in general it tends to slow down the motion of the object over the surface.

However, there is a particular case in which instead friction helps in accelerating the object.

This scenario is when a person walks: in fact, the foot of the person pushes against the floor (backward), and as a result, the floor "pushes" forward with the force of friction, which helps therefore the person to move forward. In fact, the force of friction is the force that allows us to walk forward: without the force of friction, we could not walk (think about how difficult it is to walk over an icy surface: this is because the force of friction on an icy surface is almost zero!)

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A 5.0 kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 3.0 m/s^2, find the force

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We know that m = 5 kg
a = 3.0 m/s^2
g = 9.8 (since not written, lets assume it's an international standard)

T - mg = ma

T = mg + ma

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Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.383. At what minimum rate wo

djverab [1.8K]

Answer:

25.59 m/s²

Explanation:

Using the formula for the force of static friction:

$f_s = \mu_s N$ --- (1)

where;

$f_s =$ static friction force

$\mu_s =$ coefficient of static friction

N = normal force

Also, recall that:

F = mass × acceleration

Similarly, N = mg

here, due to min. acceleration of the car;

$N = ma_{min}$

From equation (1)

$f_s = \mu_s ma_{min}$

However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.

Thus,

$F = f_s$