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mars1129 [50]
3 years ago
15

Scientific investigations

Physics
1 answer:
snow_tiger [21]3 years ago
6 0
I don’t know what you are trying to ask complete my but here are the steps to a scientific investigation i hope this helps you

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A police car parked on the side of the highway emits a 1200 Hz sound that bounces off a vehicle farther down the highway and ret
emmasim [6.3K]

f' = frequency observed by the police car after sound reflected from the vehicle and comes back to police car = 1250 Hz

f = frequency emitted by the police car  = 1200 Hz

V = speed of sound = 340 m/s

v = speed of vehicle = ?

frequency observed by the police car is given as

f' = f (V + v)/(V - v)

inserting the values in the above equation

1250 = 1200 (340 + v)/(340 - v)

v = 6.9 m/s

4 0
4 years ago
Read 2 more answers
Describe the different types of objects found in the Universe
Tema [17]
There are asteroids, which are rocks that fly through the space, and meteors which are pretty much the same. The only difference is their sizes. There are also planets, big and small. The moon, the dwarf planet Pluto, and many more. There are probably thousands of other planets that we haven't quite yet discovered. Soon we will though. There are also billions of stars, such as the sun, and some others we don't have names for that form constellations.
Hope this helped!!
4 0
3 years ago
An initially uncharged 3.67 μF capacitor and a 8.01 k Ω resistor are connected in series to a 1.50 V battery that has negligible
inn [45]

Answer:

The initial current in the circuit is 0.1873 mA

Explanation:

Given;

capacitance is given as 3.67 x 10⁻⁶ F

resistance is given as 8010 Ω

voltage across the circuit is 1.5 V

Since the capacitor is initially uncharged, the capacitive reactance is zero.

From ohms law;

Voltage across the circuit is directly proportional to the opposition to the flow of current.

V = IR

I = V/R

I = 1.5/8010

I = 0.0001873 A = 0.1873 mA

Therefore, the initial current in the circuit is 0.1873 mA

8 0
4 years ago
Two particles, each having a mass of 3.0 mg and having equal but opposite charges of magnitude of 6.0 nC, are released simultane
algol13

Answer:

The distance that separates the two particles is 7.42 cm.

Explanation:

Given;

the mass of each particle, m = 3 mg = 3 x 10⁻⁶ kg

the magnitude of charge of each particle, q = 6.0 nC

speed of each particle, v = 5.0 m/s

F = ma = \frac{kq^2}{r^2}

a = v/t

where;

a is the acceleration of the two particles

v is the final velocity

t is time

v = u + gt

5 = 0 + 9.8t

5 = 9.8t

t = 5/9.8

t = 0.51 s

a = v/t

a = 5/0.51 = 9.8 m/s²

Total force on the two particles = (2m)a = (2* 3 x 10⁻⁶)9.8

F = 5.88 x 10⁻⁵ N

Substitute in the value of F in the above equation and calculate r

F = \frac{kq^2}{r^2}

where;

k is coulomb's constant = 8.99 x 10⁹ Nm²/c²

r is the distance of separation between the two particles

F = \frac{kq^2}{r^2} \\\\r^2 = \frac{kq^2}{F}\\\\r = \sqrt{ \frac{kq^2}{F}} = \sqrt{ \frac{8.99*10^9*(6*10^{-9})^2}{5.88*10^{-5}}} = 0.0742 \ m

Therefore, the distance that separates the two particles at the instant when each has a speed of 5.0 m/s, is 7.42 cm.

7 0
3 years ago
In Bob Shaw's short story, "The Light of Other Days," he describes something called slow glass. In the story, a married couple b
dolphi86 [110]

Answer:

Consider the following calculations

Explanation:

a )  velocity of the glass is v = distance / time

= 5 X 10-3 / 7 X 365.24 X 24 X 60 X 60

v = 2.263 X 10-11 m/sec

the speed of the light in vaccum is C

C = 3 X 108 m/sec

n = C / v

n = 3 X 108 / 2.263 X 10-11

n = 1.32567 X 1019

b )  given is 40 km/hr

= 40 X 103 / 60 X 60

= 11.11 m/sec

n = C / v

n = 3 X 108 / 11.11

n = 27002700.27

5 0
3 years ago
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