What would be the y-component of a velocity vector that had a
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Answer:
Explanation:
The gravitational pull between two object is given by:
Where M and m are the masses of the object, r is the distance between the masses and G = 6.67× 10⁻¹¹ m³kg⁻¹ s⁻² is the gravitational constant.
We have to calculate the net force on Earth due to Venus, Jupiter and Saturn when they are in one line. It means when they are the closest distance.
Mass of Earth, Me = 5.98 × 10²⁴ kg
Mass of Venus, Mv = 0.815 Me
Mass of Jupiter, Mj = 318 Me
Mass of Saturn, Ms = 95.1 Me
closest distance between Earth and Venus, rv = 38 × 10⁶ km = 0.25 AU
closest distance between Jupiter and Earth, rj = 588 × 10⁶ km = 3.93 AU
closest distance between Earth and Saturn, rs = 1.2 × 10⁹ km = 8.0 AU
where 1 AU = 1.5 × 10¹¹ m
Inserting the values:
Answer:
The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N
Explanation:
The details of the given masses having gravitational attractive force between them are;
m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m
The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;
Where;
F = The gravitational force between m₁ and m₂
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
r₂ = 0.1 m + 0.15 m = 0.25 m
Therefore, we have;
The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N