Answer:
Explanation:
given,
Radius of the solid rod, R = 5.3 cm
Electric field strength,E = 22 kN/C
Let the volume charge density be ρ
From Gauss law
ε₀ is the permitivity of free space
R is the radius of the rod
and also,
ρ is the volume charge density
Hence, the volume charge density is equal to
<span>The larger the current flowing in a wire, the stronger the magnetic field
is that surrounds the wire.
That's why, if you want to make an electromagnet stronger, one way to
do it is to add another battery. By increasing the voltage, you'll increase
the current flowing in the coils of wire, and the electromagnet will be stronger.</span>
Gravitational force = G · (mass₁) · (mass₂) / (distance)
(distance²) = G · (mass₁) · (mass₂) / (Gravitational force)
G = 6.67 x 10⁻¹¹ n-m² / kg² (the "gravitational constant")
Distance² = (6.67 x 10⁻¹¹ n-m² / kg²) (28,500 kg) (2.2 x 10⁸ kg) / (39 N)
Distance² = (6.67 · 28,500 · 2.2 x 10⁻³ N-m²) / (39N)
Distance² = (418.209 N-m²) / (39N)
Distance² = 10.72 m²
<em>Distance = 3.275 meters</em>
An absurd scenario, but that's by golly what the math says with the numbers provided. I guess it's a teeny tiny planet orbiting 3.275 meters outside a teeny tiny black hole.
