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almond37 [142]
3 years ago
15

A 230 g air-track glider is attached to a spring. The glider is pushed in 8.2 cm and released. A student with a stopwatch finds

that 13 oscillations take 19.0 s . What is the spring constant? Express your answer using two significant figures.
Physics
1 answer:
Natasha_Volkova [10]3 years ago
8 0

Answer:

4.3 N/m

Explanation:

m = 230 g = 0.230 kg, x = 8.2 cm

in 13 oscillations, time taken = 19 s

In 1 oscillation, time taken = 19 / 13 = 1.46 s

By the use of formula of time period , Let k be the spring constant.

T = 2\pi \sqrt{\frac{m}{k}}

1.46 = 2\pi \sqrt{\frac{0.230}{k}}

0.054 = 0.230 / k

k = 4.26 N/m

k = 4.3 N/m

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A water skier lets go of the tow rope upon leaving the end ofa
ANTONII [103]

Answer:

1.35m

Explanation:

At the highest point of the jump, the vertical speed of the skier should be 0. So the 13m/s speed is horizontal, this speed stays the same from the jumping point to the highest point. The 14m/s speed at jumping point is the combination of both vertical and horizontal speeds.

The vertical speed at the jumping point can be computed:

v_v^2 + v_h^2 = v^2

v_v^2 + 13^2 = 14^2

v_v^2 = 196 - 169 = 27

v_v = \sqrt{27} = 5.2 m/s

When the skier jumps to the its potential energy is converted to kinetic energy:

E_p = E_k

mgh = mv_v^2/2

where m is the skier mass and h is the vertical distance traveled, v_v is the vertical velocity at jumping point, and h is the highest point.

Let g = 10m/s2

We can divide both sides of the equation by m:

gh = v_v^2/2

h = \frac{v_v^2}{2g} = \frac{27}{2*10} = 1.35 m

3 0
3 years ago
A pendulum of unknown mass is attached to the ceiling and nearly touches the floor as it completes 6 full cycles in 45 s. At its
lys-0071 [83]

Answer:

a) h = 14 m

b) h = 88 cm

c) f = 0.054 Hz

d) f = 0.13 Hz

Explanation:

a) T = 2π√(L/g)

L = T²g/4π²

L = (45/6)²(9.8) / 4π² = 13.963...

b) ½mv² = mgh

h = v²/2g

h = 4.15²/ (2(9.8)) = 0.87869

c) f = 1/T = 1 / (2π√(14 / 1.62)) = 0.0542

d) f = 6/45 = 0.13333...

6 0
3 years ago
If the current in the circuit is 10.5 A,
sergiy2304 [10]

Answer:

E) 147 V

Explanation:

Ra+Rb+Rc = 14.0

V = IR

V = (10.5)(14.0)

V = 147 V

7 0
3 years ago
A 500-watt vacuum cleaner is plugged into a 120-volt outlet and used for 30 minutes. How much current runs through the vacuum? 9
Anna [14]

Answer:

4.2amps

Explanation:

7 0
3 years ago
Read 2 more answers
Sinusoidal waves 5.00 cm in amplitude are to be transmitted along a string that has a linear mass density of 4.00× 10⁻²kg /m . T
mylen [45]

The highest frequency (f) at which the source can operate is given as:

f = 55.133Hz.

<h3>What are sinusoidal waves?</h3>

The most realistic representation of how many objects in nature change state is a sine wave or sinusoidal wave.

A sine wave depicts how the intensity of a variable varies over time.

<h3>What is the calculation justifying the above result?</h3>

P = (1/2) μω²A²v

300W = 1/2 (4 X 10⁻²kg/m) ω₂ (0.05m)²v

Thus the wave speed is:

v = √(T/μ)

= √[(100N)/(4 X 10⁻²kg/m)

= 50m/s

300W = 1/2(4 X 10⁻²kg/m) ω²(0.05m)² (50m/s)

⇒ ω = 346.41 1/s

ω = 346.41 1/s

= 2πf

⇒ f = 55.133Hz


Learn more about Sinusoidal waves:
brainly.com/question/20912200
#SPJ4

7 0
2 years ago
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