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rjkz [21]
4 years ago
15

A storage tank, used in a fermentation process, is to be rotationally molded from polyethylene plastic. This tank will have a co

nical section at the bottom, right circular cylindrical mid-section and a hemispherical dome to cover the top. The radius of the tank is 1.5 m, the cylindrical side-walls will be 4.0 m in height, and the apex of the conic section at the bottom has an included angle of 60°. If the tank is filled to the top of the cylindrical side-walls, what is the tank capacity in liters?
Engineering
1 answer:
NNADVOKAT [17]4 years ago
3 0

Answer:

The volume up to cylindrical portion is approx  32355 liters.

Explanation:

The tank is shown in the attached figure below

The volume of the whole tank is is sum of the following volumes

1) Hemisphere top

Volume of hemispherical top of radius 'r' is

V_{hem}=\frac{2}{3}\pi r^3

2) Cylindrical Middle section

Volume of cylindrical middle portion of radius 'r' and height 'h'

V_{cyl}=\pi r^2\cdot h

3) Conical bottom

Volume of conical bottom of radius'r' and angle \theta is

V_{cone}=\frac{1}{3}\pi r^3\times \frac{1}{tan(\frac{\theta }{2})}

Applying the given values we obtain the volume of the container up to cylinder is

V=\pi 1.5^2\times 4.0+\frac{1}{3}\times \frac{\pi 1.5^{3}}{tan30}=32.355m^{3}

Hence the capacity in liters is V=32.355\times 1000=32355Liters

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Write definitions for the following two functions:______
lawyer [7]

Answer:

<em>Written in Python</em>

def SumN(n):

     total = 0

     for i in range(1,n+1):

           total = total + i

     print("Total: ",total)

def SumNCubes(n):

     total = 0

     for i in range(1,n+1):

           total = total + i**3

     print("Cube: ",total)

n = int(input("User Input: "))

if n > 0:

     SumN(n)

     SumNCubes(n)

Explanation:

The SumN function is defined here

def SumN(n):

This line initializes the total to 0

     total = 0

The following iteration compute the required sum

<em>      for i in range(1,n+1): </em>

<em>            total = total + i </em>

This line outputs the calculated sum

     print("Total: ",total)

The SumNCubes function is defined here

def SumNCubes(n):

This line initializes the total to 0

     total = 0

The following iteration compute the required sum of cubes

<em>      for i in range(1,n+1): </em>

<em>            total = total + i**3 </em>

This line outputs the calculated sum of cubes

     print("Cube: ",total)

The main starts here; The first line prompts user for input

n = int(input("User Input: "))

The next line checks if input is greater than 0; If yes, the two defined functions are called

if n > 0:

     SumN(n)

     SumNCubes(n)

6 0
3 years ago
Waste that is generated by a business is called a _____________.
matrenka [14]
It is called a ‘Waste Stream’

This should be right! Hope this helps, have a great day!
8 0
3 years ago
The electric motor exerts a torque of 800 N·m on the steel shaft ABCD when it is rotating at a constant speed. Design specificat
kodGreya [7K]

Answer:

d= 4.079m ≈ 4.1m

Explanation:

calculate the shaft diameter from the torque,    \frac{τ}{r} = \frac{T}{J} = \frac{C . ∅}{l}

Where, τ = Torsional stress induced at the outer surface of the shaft (Maximum Shear stress).

r = Radius of the shaft.

T = Twisting Moment or Torque.

J = Polar moment of inertia.

C = Modulus of rigidity for the shaft material.

l = Length of the shaft.

θ = Angle of twist in radians on a length.  

Maximum Torque, ζ= τ ×  \frac{ π}{16} × d³

τ= 60 MPa

ζ= 800 N·m

800 = 60 ×  \frac{ π}{16} × d³

800= 11.78 ×  d³

d³= 800 ÷ 11.78

d³= 67.9

d= \sqrt[3]{} 67.9

d= 4.079m ≈ 4.1m

3 0
3 years ago
Read 2 more answers
Please what is the name of this tool​
madam [21]

Answer: it’s called a saw or see saw

Explanation: it works by cutting a tree, wood, tile, etc.

5 0
3 years ago
Read 2 more answers
Air is to be compressed so that its volume is reduced to half of its original volume if the initial pressure is 200 kPa and the
Alex_Xolod [135]

Answer:

P_{2} = 527.803\,kPa

Explanation:

The politropic relationship for a isentropic process is:

\frac{P_{2}}{P_{1}} = \left(\frac{V_{1}}{V_{2}}  \right)^{\gamma}

Where \gamma is the ratio of specific heats

The final pressure is:

P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}}\right)^{\gamma}

P_{2} = (200\,kPa)\cdot (2)^{1.4}

P_{2} = 527.803\,kPa

7 0
3 years ago
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