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n200080 [17]
3 years ago
7

HelpppPppppp me if u do ill give u a pringle

Mathematics
1 answer:
andreev551 [17]3 years ago
5 0

Answer:

D) 2x+10=40, x= 15 rides

Step-by-step explanation:

Since Paul only bought one ticket, then $10 is the constant of the equation. Since Paul pays $2 per ride, $2 will be the rate/coefficient of the equation.

Since we are solving for x, $40 will be on the right side of the equation

Putting these three facts together, we can make the equation 2x+10=40 which means D is correct

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The team won 10 of its 30 games and lost the rest. What was the team's win-loss ratio?
hammer [34]

Answer:

10:20

Step-by-step explanation:

8 0
3 years ago
34 divided by 2,380.
lutik1710 [3]
34/2380
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17/1190
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1/70
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4 0
4 years ago
Read 2 more answers
Please can someone help I try it hard but I don’t understand it
sammy [17]

He could have scored 7, 14, 21, 28, 35, or 42 points (all multiples of 7 less than 45).

answer: B

5 0
3 years ago
Read 2 more answers
Use the definition mtan=lim
Leokris [45]

(a) mtan refers to the slope of the tangent line. Given <em>f(x)</em> = 9 + 7<em>x</em> ², compute the difference quotient:

\dfrac{f(x+h)-f(x)}h = \dfrac{(9+7(x+h)^2)-(9+7x^2)}h = \dfrac{(9+7x^2+14xh+7h^2)-9-7x^2}h = \dfrac{14xh+7h^2}h

Then as <em>h</em> approaches 0 - bearing in mind that we're specifically considering <em>h</em> <em>near</em> 0, and not <em>h</em> = 0 - we can eliminate the factor of <em>h</em> in the numerator and denominator, so that

m_{\rm tan} = \displaystyle \lim_{h\to0}\frac{f(x+h)-f(x)}h = \lim_{h\to0}\frac{14xh+7h^2}h = \lim_{h\to0}(14x+7h) = 14x

and so the slope of the line at <em>P</em> (0, 9), for which we take <em>x</em> = 0, is 0.

(b) The equation of the tangent line is then <em>y</em> = 9.

4 0
3 years ago
What is 7√11√ in simplest radical form?<br> Enter your answer in the box.
Tpy6a [65]

Answer:

\frac{\sqrt{77} }{11}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab} and

\sqrt{a} × \sqrt{a} = a

Given

\frac{\sqrt{7} }{\sqrt{11} }

To rationalise the denominator multiply numerator/ denominator by \sqrt{11}

\frac{\sqrt{7} }{\sqrt{11} } × \frac{\sqrt{11} }{\sqrt{11} }

= \frac{\sqrt{7(11)} }{\sqrt{11(11)} }

= \frac{\sqrt{77} }{11}

7 0
3 years ago
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