Really, ionization takes place. It means the acid dissociates in water. Ionization is just a fancy way of saying dissociation. Always think easy.
Definition of IONIZATION: The process describing the dissociation of an acid in water.
If it ionizes or dissociates completely in water, then it shows that hydronium is a STRONG ACID. And if it ionizes partially, that shows hydronium is a WEAK ACID.
So, the answer will be choice B. by a process called ionization
Answer:
γ−Hydrogen is easily replacable during bromination reaction in presence of light , because Allylic substitution is being preferred.
Explanation:
that's all
Answer:
The solid particles will be trapped behind on the strainer while the liquid molecules will pass or filter through.
Explanation:
Filtration is a process of separation of mixtures involving an insoluble solid and a fluid such as liquids or gases using a filtering medium such as paper or cloth or any other material. During the process, the liquid molecules pass through the filtering medium whereas the solid particles are not allowed to pass through but are retained by the medium. The reason is that the pores on the filtering medium are only small enough for the liquid molecules to pass through but not the solid particles.
An example of a mixture that can be separated through filtration is a suspension of chalk and water. Also, a mixture of water and solid particles such as water and tea leaves can also be separated using a strainer with cloth.
In the question, if a mixture of insoluble solids in a liquid is passed through a strainer with cloth, the solid particles will be trapped behind on the strainer while the liquid molecules will pass through.
Answer:
Explanation:
1. Please provide the enthalpy info - I will work on it with the info
2.
i) Reaction a should be modified to match the number of S in equation:
2S + 2O2 -> 2SO2 deltaH = -370kJ
ii) Reaction b should be written reversely to match the reactants of SO2:
2SO2 + O2 -> 2SO3 deltaH = 256kJ
iii) Adding the equations together:
2S + 3O2 -> 2SO3
iv) Enthalpy of the combined reaction = -370+256 = -114kJ
It is negative so the reaction is exothermic.
Lattice energy U(MX2) to calculate
Use Born-Haber(-Fajans) Cycle
http://en.wikipedia.org/wiki/Born%E2%80%...
M(s) + X2 → MX2(s) ΔHf°MX2 = -957 kJ mol^-1
M(s) →ΔHsub(M)→ M(g) ΔHsub = 123kJ mol^-1
M(g) →ΔHIE1(M)→ M^+ + e⁻ 757 kJ mol^-1
M^+→ΔHIE2(M)→ M^2+ + e⁻ 1451 kJ mol^-1
X2 →ΔHBE(X2)→ 2X +153 kJ mol^-1
X + e⁻→ΔHEA(X)→ X^- -313 kJ mol^-1
ΔHfo = U + ΔHsub(M) + IE1 + IE2 + ΔHdissX2 + 2EA1(X)
-957= U + 123 + 757 + 1451 + 153 – 626 = U + 1858
U = -2815 kJ mol^-1 The –ve sign is often dropped
