Answer is: <span>the molarity of the diluted solution 0,043 M.
</span>V(NaOH) = 75 mL ÷ 1000 mL/L = 0,075 L.
c(NaOH) = 0,315 M = 0,315 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,075 L · 0,315 mol/L.
n(NaOH) = 0,023625 mol.
V(solution) = 0,475 L + 0,75 L.
c(solution) = 0,023625 mol ÷ 0,550 L.
c(solution) = 0,043 mol/L.
Single replacements since cu is being replaced by zn
Answer:
the enthalpy change of this is 5.02mol
Answer:
Volume of AgNO₃ = 4.9 ml (Approx)
Explanation:
Given:
Total solution = 75 ml
Volume of AgNO₃ = 6.5%
Find:
Volume of AgNO₃
Computation:
Volume of AgNO₃ = Total solution x Volume of AgNO₃
Volume of AgNO₃ = 75 x 6.5%
Volume of AgNO₃ = 4.875
Volume of AgNO₃ = 4.9 ml (Approx)