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galben [10]
3 years ago
6

3.

Chemistry
2 answers:
kherson [118]3 years ago
8 0

Answer: Alum is used in water treatment as a germicide

Explanation:

A. a germicide

3241004551 [841]3 years ago
6 0
Definitely A I did this in yr 8
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At room temperature, compounds that are held together by covalent bonds tend to exist in what state?
Sophie [7]

at room temperature substances hawks together by covalent bonds are typically in liquid form

6 0
3 years ago
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Which substance is an example of a colloid?
Semmy [17]

Answer:

Milk would be the only colloid

The sand and water, tomato juice and sugar and water are all known as suspensions (It consists of large particles mixed or suspended in a solution)

Explanation:

8 0
3 years ago
How many molecules of water can be produced from 46.72 liters of C8H18? 2\:C_8H_{18}\:+\:25\:O_2\:\:\Longrightarrow\:\:16\:CO_2\
Dmitry [639]

Answer:

1.13×10^25 molecules of water.

Explanation:

Equation of the reaction;

C8H18(g) + 25/2 O2 (g) -------> 8CO2(g) + 9H2O(l)

It is important to first put down the balanced reaction equation. It is not possible to solve any problem on stoichiometric relationship without a balanced reaction equation. Once the equation is obtained, we can now proceed with other steps in the solution of the problem.

From the reaction equation, 1 mole of C8H18 produces 9 moles of water

1 mole of C8H18 occupies 22.4L volume while 1 mole of water contains 6.02×10^23 molecules of water

Hence

22.4 L of C8H18 produces 9(6.02×10^23) molecules of water

46.72 L of C8H18 will produce 46.72 L × 9(6.02×10^23) molecules of water/22.4 L

= 113×10^23 or 1.13×10^25 molecules of water.

5 0
3 years ago
If 36 000 kg of full cream milk containing 4% fat is to be separated in a 6 hour period into skim milk with 0.45% fat and cream
Yuri [45]

Answer:

B=5522.33kg/h

C=478.11kg/h

Explanation:

Hi! It's a mass balance. First we have to determine the inflow.

mass flow rate = 36000kg / 6h = 6000kg / h

We define the input variable

- input flow (A) = 6000kg / h

-XgA = percentage of fat in A = 0.04

We define output variables.

- skim milk (B)

-creme (C)

-XgB = fat percentage at B = 0.0045

-XgC = percentage of fat in C = 0.45

Then we can start with the balance.

As a general rule, the mass balance is:

Input = Output

Balance sheet

1) A = B + C

Fat balance

2) A * XgA = B * XgB + C * XgC

Now we can solve.

We replace and clear B in equation 2

6000kg / h * 0.04 = B * 0.0045 + C * 0.45

B = (240kg / h) /0.045-C*0.45/0.0045

3) B = 53333.33kg / h-C * 100

We replace equation 3 in 1 and clear C

A = B + C

6000kg / h = 53333.33kg / h-C * 100 + C

C=(6000kg/h-53333.33kg/h)/(-99)

C=478.11kg/h

We replace C in equation 3 and calculate B

B = 53333.33kg / h-478.11kg/h * 100

B=5522.33kg/h

Then we have the values ​​of the outflows.

C=478.11kg/h

B=5522.33kg/h

7 0
3 years ago
What element produces violet light of approximately 412 nm?
Natali [406]
a. Hydrogen

Hydrogen has a line at 410 nm.
Mercury has a line at 405 nm.
Sodium and neon have no lines near 412 nm.
8 0
3 years ago
Read 2 more answers
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