3.

The starship Voyager, like many other vessels of the newly designed 24th-century fleet, uses antimatter as fuel.(b) When the ant

Drupady [299]

When the antimatter is atomic antihydrogen, a small amount of it is mixed with excess atomic hydrogen (gathered from interstellar space during flight).

<h3>What is antimatter ?</h3>

According to contemporary physics, antimatter is described as being made up of the opposite particles from "ordinary" matter, or their "partners." Only a few nanograms of antiparticles have been created artificially, but tiny quantities of antiparticles are produced every day at particle accelerators and in natural processes like cosmic ray collisions and some types of radioactive decay. However, only a small portion of these antiparticles have been successfully bound together in experiments to form antiatoms. Antimatter has never been built in a macroscopic amount due to its extremely high cost, complexity in synthesis, and handling.

A particle and its antiparticle, such as a proton and an antiproton, theoretically have the same mass but the opposite electric charge and other variations in quantum numbers.

To learn more about antimatter from the given link:

brainly.com/question/518346

#SPJ4

8 0

2 years ago

The standard cell potential (E°) of a voltaic cell constructed using the cell reaction below is 0.76 V:Zn (s) + (aq) ? (aq) + (g

gladu [14]

I can’t see any this what the question

8 0

4 years ago

Na2CO3 + 2HCl ---------> 2NaCl + CO2 + H2O How many moles of NaCl are produced from the reaction of 1.67 x 1022 molecules of

dexar [7]

Answer:

0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.

Explanation:

The balanced reaction is:

Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

Na₂CO₃: 1 mole
HCl: 2 moles
NaCl: 2 moles
CO₂: 1 mole
H₂O: 1 mole

On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

$amount of moles=\frac{1.67*10^{22}molecules*1mole }{6.023*10^{23}molecules}$

amount of moles= 0.0277 moles

In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

$amount of moles of NaCl=\frac{0.0277 moles of Na_{2} CO_{3}*2 moles of NaCl }{1 mole of Na_{2} CO_{3}}$

amount of moles of NaCl= 0.0554 moles

0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.

8 0

3 years ago

2.70g of Zn (s) reacts with 50.0 mL of 1.00 M HCl solution to produce hydrogen gas according to the reaction. (R = 0.08206 L·atm

Anika [276]

Answer:

a. 0.0413 moles Zn

b. 0.0500 moles HCl

c. HCl is the limiting reactant

d. 0.0250 moles H₂

e. V = 0.56L

Explanation:

The reaction of Zn(s) with HCl is:

Zn(s) + 2HCl (aq) → ZnCl₂ (aq) + H₂(g)

Where 1 mole of Zn reacts with 2 moles of HCl.

a) To convert mass in grams to moles of a substance you need to use molar mass (Molar mass Zn: 65.38g/mol), thus:

2.70g Zn × (1mol / 65.38g) = 0.0413moles of Zn

b. Now, when you have a solution in molarity (Moles / L), you can know the moles of a volume of solution, thus:

Moles HCl:

50.0mL = 0.0500L × (1.00mol / L) = 0.0500 moles HCl

c. The limiting reactant is founded by using the chemical reaction as follows:

For a complete reaction of 0.0500 moles HCl you need:

0.0500 moles HCl × (1 mole Zn / 2 moles HCl) = 0.0250 moles Zn

As you have 0.0413 moles of Zn, and you need just 0.0250 moles for the complete reaction, Zn is the exces reactant and HCl is the limiting reactant

d.As HCl is limiting reactant and 2 moles of HCl react with 1 mole of H₂, moles of hydrogen formed are:

0.0500 moles HCl × (1 mole H₂ / 2 moles HCl) = 0.0250 moles H₂

e. Using PV = nRT, you can find volume of gas, thus:

PV = nRT

V = nRT / P

Where P is pressure 1atm at STP, n are moles, R is gas consant 0.08206Latm/molK and T is absolute temperature 273.15K at STP.

V = 0.0250molesₓ0.082atmL/molKₓ273.15K / 1atm

V = 0.56L

3 0

3 years ago

Which one of the following sets of units is appropriate for a second-order rate constant?

Natalija [7]

Answer:

C. L mol-1 s-1.

Explanation:

Hello,

In this case, a rate law has the following general form:

$r=kC^x_i$

Whereas r accounts for the rate measured in M/s units, k is the rate constant whose units depends on the order of the reaction, C the concentration of the species in M units, contributing to the rate and x the order of the reaction.

In such a way, since in this case x equals two (second-order rate), the units of k turns out:

$\frac{M}{s}=\frac{mol}{L*s}=k*(\frac{mol}{L}) ^2\\\frac{mol}{L*s}=k*\frac{mol^2}{L^2}\\\\k=\frac{L^2*mol}{mol^2*L*s} \\\\k=\frac{L}{mol*s}$

Which matches with C. L mol-1 s-1.

Best regards.

5 0

3 years ago