Answers:
<u>Reduce:</u>
Here we gave to simplify the expressions:
9) 
Grouping similar terms:

Applying common factor
in the first parenthesis and common factor
in the second parenthesis:
This is the answer
11) 
Rearranging the terms:

Applying common factor
in the first parenthesis and common factor
in the second parenthesis:
This is the answer
<u>Multiply:</u>
19) 
Multiplying both fractions:

Dividing numerator and denominator by 3 and simplifying:
This is the answer
21) 

Operating with cross product:


Grouping similar terms and factoring:
This is the answer
<u>Divide:</u>
29) 

Simplifying:
This is the answer
33) 

Factoring numerator and denominator:

Simplifying:
This is the answer
37) 

Applying the distributive property in numerator and denominator:

Grouping similar terms and factoring by common factor:

Dividing by
in numerator and denominator and simplifying:
This is the answer
Answer: =86
Step-by-step explanation:
* Hopefully the picture helps:) Mark me the brainliest:)
<em>∞ 234483279c20∞</em>
True because to make a compound event you will need two dependent events
I think is this hopefully this helps
Answer:
6 , 3 should be the midpoint
Step-by-step explanation: