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3 years ago

160 pounds to kilograms

Mathematics

2 answers:

Paraphin [41]3 years ago

8 0

Answer:

160 lbs. = 72.57 kg.

AlexFokin [52]3 years ago

6 0

1 pound = 0.453592 Kg

160 * 0.453592 =

72.57472 Kg (you can round to 72.6)

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If MNO = PQR, which of the following can you conclude as being true?

EastWind [94]

<span>If MNO = PQR, which of the following can you conclude as being true?

A. No = QR

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2 years ago

Read 2 more answers

Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

spin [16.1K]

Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

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2 years ago

What is the domain of the function shown in the graph below?

Maksim231197 [3]

Answer:

Domain: (+∞, -∞)

Step-by-step explanation:

Domain = x value

hope it helps

6 0

2 years ago

Help me with this question

madreJ [45]

Answer:

Step-by-step explanation:

In the function, the growth factor is "a", the base of the exponent. When the exponent is increased by 1, the value is multiplied by "a".

f(7) = a·f(6) = 4·15

f(7) = 60

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As you know, the exponent signifies repeated multiplication. So, an increase of 1 in the exponent means the base is part of the product one more time:

a^6 = a·a·a·a·a·a

a^7 = a·a·a·a·a·a·a = a·(a^6)

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2 years ago

Yukio says the scale from DEF to ABC is 3:1. Is Yukio Correct? Explain

Angelina_Jolie [31]

Answer: Yes, Yukio is correct.

Step-by-step explanation:

Assuming that Triangle DEF and ABC have the same angles (they do because they are right-angled), we can take the length from the larger triangle (DEF) and divide it by the length of the smaller triangle (ABC).

Length of DEF = 6cm

Length of ABC = 2cm

= 6/2

= 3

Proves that scale of DEF to ABC is 3:1

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3 years ago