NaHCO₃ + H⁺ = Na⁺ + H₂O + CO₂
n(NaHCO₃)=n(H⁺)
m(NaHCO₃)=M(NaHCO₃)n(NaHCO₃)=M(NaHCO₃)n(H⁺)
p=$m(NaHCO₃)=$M(NaHCO₃)n(H⁺)
p=9.20$/kg×84.0kg/kmol×10⁻³kmol=0.7728$
p≈0.77$
1 mole --------- 22.4 L at ( STP )
? moles ------- 131.97 L
131.97 x 1 / 22.4 => 5.8915 moles
Therefore:
1 mole ------------- 6.02x10²³ atoms
5.8915 moles ----- ??
5.8915 x ( 6.02x10²³) / 1 =
= 3.5448x10²⁴ atoms
hope this helps!
Answer :
1.80 x 10^-4 moles/liter OH-
Explanation:
pH = 3.58 ; [H3O+] = 10^-3.58 = 2.63 x 10^-4 moles/liter
pH = 4.08 ; [H3O+] = 10^-4.08 = 8.32 x 10^-5 moles/liter
One needs to remove:
2.63 x 10^-4 moles/liter – 8.32 x 10^-5 = 1.80 x 10^-4 moles H3O+/liter
According to the equation: H3O+ + OH-=⇒ 2H2O
Moles/ liter of OH- needed:
1.80 x 10^-4 moles H3O+/liter x 1 mole OH-/1mole H3O+ = 1.80 x 10^-4 moles/liter OH-
Answer:
CnH2n+2 formula
Explanation:
Alkanes have the general formula CnH2n+2, so if an alkane had 7 carbon atoms, it would have the molecular formula C7H16.