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Sever21 [200]
3 years ago
5

The following figure represents the formation of an ionic compound. Substances A and B are initially uncharged, but when mixed e

lectrons are transferred. Using the figure, identify which substance will form the cation and which will form the anion. Provide a brief (one or two sentences) explanation for your response. (Hint: How does losing electrons affect atomic radii?)

Chemistry
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

This question is incomplete

Explanation:

This question is incomplete but some general explanation provides a clear answer to what is been asked in the question.

An ionic/electrovalent compound is a compound whose constituent atoms are joined together by ionic bond. Ionic bond is a bond involving the transfer of valence electron(s) from an atom (to form a positively charged cation) to another  atom (to form a  negatively charged anion). The atom transferring is usually a metal while the atom receiving is usually a non-metal.

For example (as shown in the attachment), in the formation of NaCl salt, the sodium (Na) transfers the single electron (valence) on it's outermost shell to chlorine (Cl) which ordinarily has 7 electrons on it's outermost shell but becomes 8 after receiving the valence electron from sodium. It should also be noted that Na is a metal while Cl is a non-metal.

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Which of the following is produced when two or more elements combine in a chemical reaction?
eimsori [14]

Answer:

a compound i think

Explanation:

7 0
2 years ago
The value of Kp for the reaction NO(g) 1 1 2 O2(g) 4 NO2(g) is 1.5 3 106 at 25°C. At equilibrium, what is the ratio of PNO2 to P
expeople1 [14]

Answer : The ratio of p_{NO_2} to p_{NO} is, 6.87\times 10^5

Solution :  Given,

K_p=1.5\times 10^6

p_{O_2} = 0.21 atm

The given equilibrium reaction is,

NO(g)+\frac{1}{2}O_2\rightleftharpoons NO_2(g)

The expression of K_p will be,

K_p=\frac{(p_{NO_2})}{(p_{NO})\times (p_{O_2})^{\frac{1}{2}}}

Now put all the given values in this expression, we get:

1.5\times 10^6=\frac{(p_{NO_2})}{(p_{NO})\times (0.21)^{\frac{1}{2}}}

\frac{(p_{NO_2})}{(p_{NO})}=(1.5\times 10^6)\times (0.21)^{\frac{1}{2}}

\frac{(p_{NO_2})}{(p_{NO})}=6.87\times 10^5

Therefore, the ratio of p_{NO_2} to p_{NO} is, 6.87\times 10^5

5 0
3 years ago
Formula for Sodium Hydrogen Carbonate NaHCO3? or Na2HCO3?
yan [13]

NaHCO3 is the right answer

8 0
3 years ago
During chemical reactions the bonds between atoms break and new bonds form. Energy must be absorbed to break a bond, so breaking
ss7ja [257]

Answer:

The equation is: CuCO3(s) → CuO(s) + CO2(g)

Explanation:

Copper carbonate decomposes at high temperatures, generating the products carbon dioxide (CO2) and copper oxide (II) CuO. In this type of decomposition reaction, a substance is broken generating two different compounds.

7 0
3 years ago
Problem Page A chemist measures the amount of bromine liquid produced during an experiment. He finds that of bromine liquid is p
masha68 [24]

The question is incomplete, here is the complete question:

A chemist measures the amount of bromine liquid produced during an experiment. She finds that 766.g of bromine liquid is produced. Calculate the number of moles of bromine liquid produced. Round your answer to 3 significant digits.

<u>Answer:</u> The amount of liquid bromine produced is 4.79 moles.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Given mass of liquid bromine = 766. g

Molar mass of liquid bromine, (Br_2) = 159.8 g/mol

Putting values in above equation, we get:

\text{Moles of liquid bromine}=\frac{766.g}{159.8g/mol}=4.79mol

Hence, the amount of liquid bromine produced is 4.79 moles.

6 0
3 years ago
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