1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sever21 [200]
3 years ago
5

The following figure represents the formation of an ionic compound. Substances A and B are initially uncharged, but when mixed e

lectrons are transferred. Using the figure, identify which substance will form the cation and which will form the anion. Provide a brief (one or two sentences) explanation for your response. (Hint: How does losing electrons affect atomic radii?)

Chemistry
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

This question is incomplete

Explanation:

This question is incomplete but some general explanation provides a clear answer to what is been asked in the question.

An ionic/electrovalent compound is a compound whose constituent atoms are joined together by ionic bond. Ionic bond is a bond involving the transfer of valence electron(s) from an atom (to form a positively charged cation) to another  atom (to form a  negatively charged anion). The atom transferring is usually a metal while the atom receiving is usually a non-metal.

For example (as shown in the attachment), in the formation of NaCl salt, the sodium (Na) transfers the single electron (valence) on it's outermost shell to chlorine (Cl) which ordinarily has 7 electrons on it's outermost shell but becomes 8 after receiving the valence electron from sodium. It should also be noted that Na is a metal while Cl is a non-metal.

You might be interested in
How many moles of H2 would be required to produce 37.0 moles of water?
svp [43]

Hii there !

The reaction accompanying production of water in this case would be -

\green{ \underline { \boxed{ \sf{H_2+ \frac{1}{2}O_2\longrightarrow H_2O}}}}

Thus ,by observing the reaction, we can conclude that 1 mole of Hydrogen (H_2)react with 1/2 mole of oxygen(O_2)to produce 1 mole of water (H_2O)

\impliesTherefore, 37.0 moles of hydrogen(H_2) will be required to produce 37.0 moles of water.

Hope it helps.

7 0
2 years ago
Which 0.1 M solution has a pH greater than 7?<br> w<br> 1. C6H1206<br> 2.CH3COOH<br> 3.КСІ<br> 4.KOH
Marrrta [24]

Answer:

4) KOH

Explanation:

Trust

8 0
3 years ago
HELP. NO FAKE ANSWERS. I WILL REPORT. I AM CONFUSED AND NEED HELP. FILL IN THE NOT FILLED BOXES POR FAVOR.
SCORPION-xisa [38]
Question #1
Potasium hydroxide (known)
 volume used is 25 ml 
Molarity (concentration) = 0.150 M
Moles of KOH used 
           0.150 × 25/1000 = 0.00375 moles
Sulfuric acid (H2SO4) 
volume used = 15.0 ml
unknown concentration
The equation for the reaction is
2KOH (aq)+ H2SO4(aq) = K2SO4(aq) + 2H2O(l) 
Thus, the Mole ratio of KOH to H2SO4 is 2:1
Therefore, moles of H2SO4 used will be;
      0.00375 × 1/2 = 0.001875 moles
Acid (sulfuric acid)  concentration
    0.001875 moles × 1000/15  
        = 0.125 M

Question #2
Hydrogen bromide (acid)
Volume used = 30 ml
Concentration is 0.250 M
Moles of HBr used;
      0.25 × 30/1000
        =  0.0075 moles 
Sodium Hydroxide (base)
Volume used 20 ml 
Concentration (unknown)
The equation for the reaction is 
NaOH + HBr = NaBr + H2O
The mole ratio of NaOH : HBr   is 1 : 1
Therefore, moles of NaOH used;
                 = 0.0075 moles
NaOH concentration will be 
       = 0.0075 moles × 1000/20
       = 0.375 M

7 0
3 years ago
2 H2S(g) ⇄ 2 H2(g) + S2(g) Kc = 9.3× 10-8 at 400ºC 0.47 moles of H2S are placed in a 3.0 L container and the system is allowed t
Anon25 [30]

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

<u>Explanation:</u>

We are given:

Initial moles of hydrogen sulfide gas = 0.47 moles

Volume of the container = 3.0 L

The molarity of solution is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of the solution}}

So, \text{Initial molarity of hydrogen sulfide gas}=\frac{0.47}{3}=0.1567M

The given chemical equation follows:

                          2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

<u>Initial:</u>                  0.1567

<u>At eqllm:</u>           0.1567-2x       2x         x

The expression of K_c for above equation follows:

K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}

We are given:

K_c=9.3\times 10^{-8}

Putting values in above equation, we get:

9.3\times 10^{-8}=\frac{(2x)^2\times x}{(0.1567-2x)^2}\\\\x=8.24\times 10^{-4}

So, equilibrium concentration of hydrogen gas = 2x=(2\times 8.24\times 10^{-4})=1.648\times 10^{-3}M

Hence, the concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

7 0
3 years ago
Brandon is trying to remember how the physical and chemical properties of metals, nonmetals, and metalloids compare. He wrote so
g100num [7]

Answer:

The correct ones are:

|

|||

|V

V

Explanation:

7 0
3 years ago
Other questions:
  • Please help me with this science question ASAP (99 points don't answer wrong just for free points)
    14·2 answers
  • When a solid mixture of mgco3 and caco3 is heated strongly, carbon dioxide gas is given off and a solid mixture of mgo and cao i
    6·1 answer
  • Which substance has Hf defined as 0 kJ/mol?
    15·1 answer
  • Which formula represents a molecular compound
    7·1 answer
  • Some isotopes of elements are unstable
    8·1 answer
  • Amning At Home -Chemisu
    15·1 answer
  • You are given 0.39 mol of niobium (Nb). How many grams of niobium do you have?
    14·1 answer
  • What volume would 0.853 moles of Nitrogen gas occupy at STP?
    14·1 answer
  • How do you know if you have a balanced equation?
    11·1 answer
  • How many significant figures are there in<br> 9.710 x 10-4
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!