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mars1129 [50]
3 years ago
8

How do you write a message?

Chemistry
2 answers:
ch4aika [34]3 years ago
8 0

Answer:

By typing with a keyboard....

Explanation:

Vilka [71]3 years ago
5 0

Answer:

re clear. Try to convey your meaning as simply as possible. Don't over-write or use exorbitant language. ...

Are complete. Include all relevant information. Think about the situation from your readers' perspective. ...

Are correct. Always proofread before sending any message.

Explanation:

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Which substance found in fossil fuels can form a harmful acid when the fuel is burned?
dem82 [27]
<span>fossil fuels are mainly organic compounds.Combustion of fossil fuels also produces other air pollutants, such as nitrogen oxides, sulfur dioxide, volatile organic compounds and heavy metals.so,substances which contain sulphur cause to form harmful acids like sulphuric and sulphurus acids</span>
3 0
2 years ago
Read 2 more answers
What is the concentration of a 1:10 dilution of a 2.5 M solution of NaCl? How would you prepare exactly 100 ml of such a solutio
Marina CMI [18]

<u>Answer:</u> The concentration of the solution is 0.25 M

<u>Explanation:</u>

Let the volume of solution of 2.5 M NaCl be 10 mL

We are given:

Dilution ratio = 1 : 10

So, the solution prepared will have a volume of = \frac{10}{1}\times 1000=100mL

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated NaCl solution

M_2\text{ and }V_2 are the molarity and volume of diluted NaCl solution

We are given:

M_1=2.5M\\V_1=10mL\\M_2=?M\\V_2=100mL

Putting values in above equation, we get:

2.5\times 10=M_2\times 100\\\\M_2=\frac{2.5\times 10}{100}=0.25M

Hence, the concentration of the solution is 0.25 M

6 0
3 years ago
How could an increase in industrial activity in developing nations contribute to global climate change?
netineya [11]
If there is an increase in industrial activity, that means that more heat will be dissipated to the atmosphere in the form of carbon dioxide. Industrialization requires fuel to keep the processes on the go. At the end of the pipeline, the combustion of fuel would result to carbon dioxide released to the atmosphere. That's how it is contributing to the global climate change through the greenhouse effect.
6 0
2 years ago
An ordered list of chemical substances is shown.
alina1380 [7]

Answer : The correct option is, (C) 2, 4 and 5.

Explanation :

Combustion reaction : It is a type of reaction in which a hydrocarbon react with an oxygen molecule to give carbon dioxide, water as a product.

For example : Methane react with oxygen to give carbon dioxide and water.

CH_4+2O_2\rightarrow CO_2+2H_2O

In the given list of chemical substances, CuO,Cu_2O,Li_2O are in oxide form. They can not be both reactant and product of a single combustion reaction.

In the given list, C_2H_5NH_2 is the only hydrocarbon which shows a combustion reaction. That means C_2H_5NH_2 react with O_2 to give CO_2,H_2O and N_2 as a product.

The balanced combustion reaction of C_2H_5NH_2 is,

20C_2H_5NH_2+40O_2\rightarrow 40CO_2+7H_2O+10N_2

Therefore, the correct answer is, (C) 2, 4, and 5.

8 0
3 years ago
3.
sineoko [7]

Answer:

3. V = 0.2673 L

4. V = 2.4314 L

5. V = 0.262 L

6. V = 2.224 L

Explanation:

3. assuming ideal gas:

  • PV = RTn

∴ R = 0.082 atm.L/K.mol

∴ V1 = 225 L

∴ T1 = 175 K

∴ P1 = 150 KPa = 1.48038 atm

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(175 K))/((1.48038 atm)(225 L))

⇒ n = 0.043 mol

∴ T2 = 112 K

∴ P2 = P1 = 150 KPa = 1.48038 atm

⇒ V2 = RT2n/P2

⇒ V2 = ((0.082 atm.L/K.mol)(112 K)(0.043 mol))/(1.48038 atm)

⇒ V2 = 0.2673 L

4. gas is heated at a constant pressure

∴ T1 = 180 K

∴ P = 1 atm

∴ V1 = 44.8 L

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(180 K))/((1 atm)(44.8 L))

⇒ n = 0.3295 mol

∴ T2 = 90 K

⇒ V2 = RT2n/P

⇒ V2 = ((0.082 atm.L/K.mol)(90 K)(0.3295 mol))/(1 atm)

⇒ V2 = 2.4314 L

5.  V1 = 200 L

∴ P1 = 50 KPa = 0.4935 atm

∴ T1 = 271 K

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(271 K))/((0.4935 atm)(200 L))

⇒ n = 0.2251 mol

∴ P2 = 100 Kpa = 0.9869 atm

∴ T2 = 14 K

⇒ V2 = RT2n/P2

⇒ V2 = ((0.082 atm.L/K.mol)(14 K)(0.2251 mol))/(0.9869 atm)

⇒ V2 = 0.262 L

6.a)  ∴ V1 = 24.6 L

∴ P1 = 10 atm

∴ T1 = 25°C = 298 K

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(298 K))/((10 atm)(24.6 L))

⇒ n = 0.0993 mol

∴ T2 = 273 K

∴ P2 = 101.3 KPa = 0.9997 atm

⇒ V2 = RT2n/P2

⇒ V2 = ((0.082 atm.L/K.mol)(273 K)(0.0993 mol))/(0.9997 atm)

⇒ V2 = 2.224 L

3 0
3 years ago
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