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mars1129 [50]
4 years ago
8

How do you write a message?

Chemistry
2 answers:
ch4aika [34]4 years ago
8 0

Answer:

By typing with a keyboard....

Explanation:

Vilka [71]4 years ago
5 0

Answer:

re clear. Try to convey your meaning as simply as possible. Don't over-write or use exorbitant language. ...

Are complete. Include all relevant information. Think about the situation from your readers' perspective. ...

Are correct. Always proofread before sending any message.

Explanation:

You might be interested in
What is the volume of 1.50 lb (pounds) of mercury? The density of mercury is 13.546 g/mL. Use the conversion that 1 kg = 2.20 lb
Arada [10]

Answer:

50.3mL of mercury are in 1.50lb

Explanation:

Punds are an unit of mass. To convert mass to volume we must use density (13.546g/mL). Now, As you can see, density is in grams but the mass of mercury is in pounds. That means we need first, to convert pounds to grams to use density and obtain volume of mercury.

<em>Mass mercury in grams:</em>

1.50lb * (1kg / 2.20lb) = 0.682kg = 682g of mercury.

<em>Volume of mercury:</em>

682g Mercury * (1mL / 13.546g) =

<h3>50.3mL of mercury are in 1.50lb</h3>
7 0
4 years ago
A piece of unknown solid substance weighs 437.2 g, and requires 8460 J to increase its temperature from 19.3 °C to 68.9 °C.What
Pachacha [2.7K]

Answer:

0.3832

Explanation:

Givens

m = 437.2 grams

c = ?

delta t = 69.8 - 19.3

H = 8460 J

Formula

H = m*c*Δt

Solution

8460 = 437.2 * c * (69.8 - 19.3)

8460 = 437.2 * c * 50.5

8460 = 22078.6 * c

c = 8460 / 22078,6

c = .3832 J / (oC * gr)

3 0
3 years ago
500 mL of He at 300 K is heated to 450 K. Find V2
ruslelena [56]

Answer:

V2 = 0.75 L

Explanation:

assumin ideal gas:

  • PV = RTn

∴ T1 = 300K

∴ V1 = 0.500 L

∴ T2 = 450 K

⇒ V2 = ?

assuming P, n constant:

⇒ PV1 = RT1n

⇒ V1/T1 = Rn/P = K..........(1)

⇒ V2/T2 = RN/P = K..........(2)

(1) = (2):

⇒ V1/T1 = V2/T2

⇒ V2 = (V1/T1)T2

⇒ V2 = (0.500 L/300 K)(450 K)

⇒ V2 = 0.75 L

8 0
3 years ago
Why does magnesium have a larger atomic radius that chlorine
sesenic [268]

Magnesium AR: 150 pm

Chlorine AR: 100 pm


8 0
4 years ago
A chemistry student needs 30,0 mL of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the stu
Marta_Voda [28]

Answer:

1.878g

Explanation:

Volume = 30.0ml

Density = 0.626gcm−3

Mass = ?

Be careful in this kind of questions to check for the units. In this case one has to remember 1 mL equal 1 cm³ so density = 0.626g/ml

The relationship between all three parameters is given by the equationn below;

Mass = Density * Volume

Mass = 0.626g/ml * 30 = 1.878g

8 0
3 years ago
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