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3 years ago

If the internal energy of a system increases but there is no change in temperature, then the system's energy is increasing.

Chemistry

2 answers:

777dan777 [17]3 years ago

4 0

Answer:

kintic

Explanation:

Rina8888 [55]3 years ago

4 0

Answer:

The system's potential energy is increasing.

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In Part A, you found the amount of product (1.80 mol P2O5 ) formed from the given amount of phosphorus and excess oxygen. In Par

Finger [1]

First step is to balance the reaction equation. Hence we get P4 + 5 O2 => 2 P2O5

Second, we calculate the amounts we start with

P4: 112 g = 112 g/ 124 g/mol – 0.903 mol

O2: 112 g = 112 g / 32 g/mol = 3.5 mol

Lastly, we calculate the amount of P2O5 produced.

2.5 mol of O2 will react with 0.7 mol of P2O5 to produce 1.4 mol of P2O5.

This is 1.4 * (31*2 + 16*5) = 198.8 g

3 0

3 years ago

5. for the following measurements is expressed to three significant figures? a) 0.007 m b) 7077 mg c) 7.30 x 10^-7 km d) 0.070

Maksim231197 [3]

The answer is c
a) 1 sf
b) 4 sf
d) 2 sf

6 0

3 years ago

How many grams of helium must be released to reduce the pressure to 65 atmatm assuming ideal gas behavior? Express the answer in

lyudmila [28]

The question is incomplete, here is the complete question:

How many grams of helium must be released to reduce the pressure to 65 atm assuming ideal gas behavior. Note : 334-mL cylinder for use in chemistry lectures contains 5.209 g of helium at 23°C.

<u>Answer:</u> The mass of helium released is 1.6 grams

<u>Explanation:</u>

We are given:

Mass of helium in the cylinder = 5.209 g

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

Or,

$PV=\frac{w}{M}RT$

where,

P = Pressure of the gas = 65 atm

V = Volume of the gas = 334 mL = 0.334 L (Conversion factor: 1 L = 1000 mL)

w = Weight of the gas = ?

M = Molar mass of helium gas = 4 g/mol

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = Temperature of the gas = $23^oC=[23+273]K=296K$

Putting values in above equation, we get:

$65atm\times 0.334L=\frac{w}{4g/mol}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 296K\\\\w=\frac{65\times 0.334\times 4}{0.0821\times 296}=3.573g$

Mass of helium released = (5.209 - 3.573) g = 1.636 g = 1.6 g

Hence, the mass of helium released is 1.6 grams

5 0

3 years ago

What is the shape of a molecule that has 4 atoms bonded to a central atom

Nataliya [291]

Answer:

C. Tetrahedral

Explanation:

Tetrahedral would be the correct choice because the central atom has 4 domains (1 bond counts as 1 domain so 4 bonds =4) and no lone pairs which means it has tetra (which translates to four) domains hence tetrahedral.

4 0

3 years ago

A sample of calcium carbonate weighs 2.1 kilograms (kg). There are 1,000 grams (g) in 1 kg, and 1 Times. 109 nanograms (ng) in 1

TiliK225 [7]

Answer:

2.1 x 10¹²ng

Explanation:

Mass of the calcium carbonate given is:

2.1kg

We need to take this mass to nanogram, ng.

Since :

1000g = 1kg

10⁹g = 1ng

So;

1kg = 1000 x 10⁹ = 10¹²ng

So;

2.1kg will give;

Since

1kg gives 10¹²ng

2.1kg will give 2.1 x 10¹²ng

5 0

2 years ago