Step-by-step explanation:
[ Refer to the attachment ]
The coordinate grid shows the graph of four equations:
2 answers:
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Answer:
Step-by-step explanation:
The equation of the line through the point &
can be represented by:
Making m the subject;
∴
we need to carry out the equation of the line through (0,1) and (1,2)
i.e
y - 1 = m(x - 0)
y - 1 = mx
where;
m = 1
Thus;
y - 1 = (1)x
y - 1 = x ---- (1)
The equation of the line through (1,2) & (4,1) is:
y -2 = m (x - 1)
where;
∴
-3(y-2) = x - 1
-3y + 6 = x - 1
x = -3y + 7
Thus: for equation of two lines
x = y - 1
x = -3y + 7
i.e.
y - 1 = -3y + 7
y + 3y = 1 + 7
4y = 8
y = 2
Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7
∴
Easy, showing work,
using the method FOIL (First,Outer,Inner, Last)
Take, (x+3)(x+5) and multiply,
First,
x*x=
Outer,
x*5=5x
Inner,
3*x=3x
Last,
3*5=15
Add the terms together,
+8x+15 (+5x+3x+15)
Thus, your answer.
using the method FOIL (First,Outer,Inner, Last)
Take, (x+3)(x+5) and multiply,
First,
x*x=
Outer,
x*5=5x
Inner,
3*x=3x
Last,
3*5=15
Add the terms together,
Thus, your answer.